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3 years ago

Tìm x a) 4x^2-12x=-9

Mathematics

1 answer:

DaniilM [7]3 years ago

5 0

Just told you : first know by heart remarkable identities !

Then apply :

4x²-12x = -9

4x²-12x +9 =0

(2x-3)² = 0

(2x-3) (2x-3) = 0

Now you have a double solution :

2x-3 = 0

and 2x -3 = 0

I let you try !

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PHYSICS As a ray of light meets a mirror, the light

Lady bird [3.3K]

<h3>Answer: 37 degrees</h3>

========================================================

Explanation:

The angle of incidence is equal to the angle of reflection. The angle of light coming in is the same as the angle of light bouncing out. Each angle is made with the dashed line as the diagram shows.

So angle RMI = 106 is bisected, i.e. divided in half, to get

Angle RMN = 53
Angle NMI = 53

since 106/2 = 53

Then notice that the horizontal dashed line is perpendicular to the vertical mirror. This means angle NMJ is a 90 degree angle and,

angle RMJ = (angle NMJ) - (angle RMN)

angle RMJ = 90 - 53

angle RMJ = 37 degrees

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In short: divide 106 in half to get 53, then subtract it from 90

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2 years ago

Which shows the numbers Nine-tenths, 0.3, 0.8, Five-tenths, and Two-tenths in order from least to greatest?

nevsk [136]

Answer:

Step-by-step explanation:

Let's express all the given numbers as decimals:

nine tenths- 0.9

0.3

0.8

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Ordering them from least to greatest:

two tenths, 0.3, five tenths, 0.8, nine tenths

7 0

3 years ago

Read 2 more answers

Can anyone help me find the coordinates (?,?) given that the shape is a parallelogram? (15 points)

xxTIMURxx [149]

The missing coordinates of the parallelogram is (m + h, n).

Solution:

Diagonals of the parallelogram bisect each other.

Solve using mid-point formula:

$$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right )$

Here $x_1=m, y_1=n, x_2=h, y_2=0$

$$=\left( \frac{m+h}{2}, \frac{n+0}{2}\right )$

$$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n}{2}\right )$

<u>To find the missing coordinate:</u>

Let the missing coordinates by x and y.

Here $x_1=0, y_1=0, x_2=x, y_2=y$

$$\text{Midpoint}=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{x}{2}, \frac{y}{2}\right )$

Now equate the x-coordinate.

$$ \frac{m+h}{2}=\frac{x}{2}$

Multiply by 2 on both sides of the equation, we get

m + h = x

x = m + h

Now equate the y-coordinate.

$$\frac{n}{2} = \frac{y}{2}$

Multiply by 2 on both sides of the equation, we get

n = y

y = n

Hence the missing coordinates of the parallelogram is (m + h, n).

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