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3 years ago

. Cho biểu thức A = |3x -1| - (x -7)

Mathematics

1 answer:

11111nata11111 [884]3 years ago

7 0

Step-by-step explanation:

which language is right

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Consider the following function. f(x) = |x − 9| Find the derivative from the left at x = 9. If it does not exist, enter NONE. -1

nydimaria [60]

Answer with Step-by-step explanation:

We are given that

$f(x)=\mid x-9\mid$

$f(x)=-(x-9)$ when x<9

$f(x)=x-9$ when $x\geq 9$

LHD

$\lim_{x\rightarrow 9-}f'(x)$

= $-\lim_{x\rightarrow 9-}(x-9)=-1$

RHD

$\lim_{x\rightarrow 9+}f'(x)$

$=\lim_{x\rightarrow 9+}(x-9)=1$

$LHD\neq RHD$

Hence, the function is not differentiable at x=9

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3 years ago

The cost of text books for school increases with the average class size identify the independent and dependent quantity in the s

Zinaida [17]

C average class size; cost

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3 years ago

Read 2 more answers

What is <br> 162divide[6 multiply (7-4) to the second power]<br> help please

Setler [38]

Answer:

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Step-by-step explanation:

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1 year ago

The average (arithmetic mean) of five different positive integers is 30. What is the greatest possible value of one of these int

geniusboy [140]

Answer:

The Greatest possible value of one of the integer is 140.

Step-by-step explanation:

Given: The average (arithmetic mean) of five different positive integers is 30.

To find: What is the greatest possible value of one of these integers?

Explanation: we are given that the arithmetic mean of five positive integer

is 30.

Let the five positive integers are A,B,C,D,E

The arithmetic mean :

$\frac{A+B+C+D+E}{5}$ =30.

On multiplying both side by 5.

A+B+C+D+E =150.

The least values of A ,B,C and D can be 1 ,2,3,4.

Then : 1 +2+3+4+E =150

On simplification 10+E =150

On subtraction both side by 10 we get

E = 140 .

Therefore, the Greatest possible value of one of the integer is 140.

6 0

3 years ago

A hair salon completed a survey of 367 customers about satisfaction with service(Dissatisfied, Neutral, Satisfied, or Very Satis

mamaluj [8]

The results of the survey are shown in the table.

It's required to calculate the following probabilities:

a) A customer is neutral

The row labeled as 'Neutral' has a total of 79 customers out of 367 in total.

The required probability is:

$p=\frac{79}{367}$

b) A customer is a walk-in

The first column labeled as 'Walk-in' has a total of 106 customers out of 367. The required probability is

$p=\frac{106}{367}$

c) A customer is dissatisfied and a walk-in.

We have to cross the row Dissatisfied with the column Walk-in. The number of customers that have both categories is 22 out of 367.

The required probability is:

$p=\frac{22}{367}$

d) A customer is very satisfied given he saw a TV ad.

This is a conditional probability, where the total is 111 because is the given condition. The customers that have both characteristics are 33, thus the required probability is:

$p=\frac{33}{111}=\frac{11}{37}$

e) A customer is satisfied or referred.

Total satisfied = 139

Total referred = 150

With both features = 62

Total customers with one or both features: 139 + 150 - 62 = 227

We have to subtract the common feature because it was counted twice.

The required probability is:

$p=\frac{227}{367}$

6 0

1 year ago