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Masja [62]
3 years ago
7

Look at image help plz!! Worth 30 points!

Mathematics
1 answer:
Leona [35]3 years ago
6 0

Answer:

t = Gx + a

Step-by-step explanation:

G = t - a/x             (Given)

G(x) = (t - a/x)x     (Multiply x on both sides)

Gx = t - a              (Simplify)

Gx + a = t - a + a  (Add a on both sides)

Gx + a = t             (Simplify)

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<img src="https://tex.z-dn.net/?f=lg%20%5Cfrac%7B1%7D%7B256%7D%20%20-%20lg%20%5Cfrac%7B125%7D%7B4%7D%20%20-%203%20lg%20%5Cfrac%7
salantis [7]

Answer:

0

Step-by-step explanation:

log 1/256 - log 125/4

= log ( 1/256 * 4/125)

= log (1/8000)

log (1/8000)  - 3 log 1/20)

Now  3 log 1/20 = log (1/20)^3 = log (1 / 8000) so we get

log (1 / 8000) - log (1 / 8000)

= 0






7 0
3 years ago
Is -3 an expression
Natalija [7]

Answer:

yeah it is an expression

Explanation:

An expression may refer to any of the following:

A combination of letters, numbers, or symbols used to represent a value of a variable. ..

4 0
4 years ago
D = a - b - c solve for b
enot [183]

To isolate b, add a and subtract c to the entire equation:

D - a + c = -b

Muliply b by -1 to eliminate the negative:

-D + a - c = b

5 0
3 years ago
Assume that the one-way commute time of an UoU student from his house to school is a normally distributed random variable which
Marizza181 [45]

Answer:

n=(\frac{1.960(10)}{5})^2 =15.36 \approx 16

So the answer for this case would be n=16 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=10 represent the sample standard deviation

n represent the sample size  

ME=5 represent the margin of error

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (2)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (2) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (3)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.96, replacing into formula (3) we got:

n=(\frac{1.960(10)}{5})^2 =15.36 \approx 16

So the answer for this case would be n=16 rounded up to the nearest integer

3 0
4 years ago
Austin made a pile of 16 snowball fight. He wants to divide them so he and his 3 friends get an equal amount. How many snowballs
sweet [91]

You divide 16/4 and get 4.

Each friend will get 4 snowballs.

4 0
4 years ago
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