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ra1l [238]
3 years ago
9

B1%7D%7B20%7D%20" id="TexFormula1" title="lg \frac{1}{256} - lg \frac{125}{4} - 3 lg \frac{1}{20} " alt="lg \frac{1}{256} - lg \frac{125}{4} - 3 lg \frac{1}{20} " align="absmiddle" class="latex-formula">
pls answer this question
Mathematics
1 answer:
salantis [7]3 years ago
7 0

Answer:

0

Step-by-step explanation:

log 1/256 - log 125/4

= log ( 1/256 * 4/125)

= log (1/8000)

log (1/8000)  - 3 log 1/20)

Now  3 log 1/20 = log (1/20)^3 = log (1 / 8000) so we get

log (1 / 8000) - log (1 / 8000)

= 0






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klemol [59]

Answer:

\frac{9}{32}  =  \frac{{10}^{2b} }{{10}^{5a}}

Step-by-step explanation:

It is given that:

log 2=a and log 3=b

This implies that:

2 =  {10}^{a}

and

3 =  {10}^{b}

Now we know that:

\frac{9}{32}  =  \frac{ {3}^{2} }{ {2}^{5} }

We substitute to get:

\frac{9}{32}  =  \frac{ ({10}^{b}) ^{2} }{( {10}^{a})^{5} }

We simplify to get:

\frac{9}{32}  =  \frac{{10}^{2b} }{{10}^{5a}}

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