Question

How much of a(n) 80% orange juice drink must be mixed with 12 gallons of a 40% orange juice drink to obtain a mixture that is 50% orange juice?
The amount of 80%orange juice drink is

Answer 1

Step-by-step explanation:

how much of an 80% orange juice drink must be mized with 20 gallons of a 20% orange juice drink to obtain a mixture that is 50% orange juice

Answer by mananth(16075) (Show Source): You can put this solution on YOUR website!

--------percent ---------------- quantity

Orange juice 20 ---------------- 20 gal

Orange juice 80 ---------------- x gal

Mixture 50 ---------------- 20 + x gal

20 * 20 + 80 x = 50 ( 20 + x )

400 + 80 x = 1000 + 50 x

80 x + -50 x = 1000 - -400

30 x = 600

/ 30

x = 20

20 gal of 80 % Orange juice