$\frac{sinA}{a} =\frac{sinB}{b} =\frac{sinC}{c} \\\frac{sin \angle XYZ}{19} =\frac{sin 62}{24} \\sin \angle XYZ=\frac{19}{24} \times sin 62\\\angle ~XYZ=sin^{-1}(\frac{19}{24} \times ~sin~62) \approx 44.35^\circ$

7 0

2 years ago

How many meter is a desk and a bicycle

Elan Coil [88]

It could be 1.85 meters for an adult bike.

4 0

3 years ago

Read 2 more answers

What is the vertex of the graph of the following equation? y = x^2 + 2x-3

ExtremeBDS [4]

Answer:

vertex = (- 1, - 4 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = - $\frac{b}{2a}$

y = x² + 2x - 3 ← is in standard form

with a = 1, b = 2 , then

x = - $\frac{2}{2}$ = - 1

Substitute x = - 1 into the equation for corresponding value of y

y = (- 1)² + 2(- 1) - 3 = 1 - 2 - 3 = - 4

vertex = (- 1, - 4 )

6 0

3 years ago

What is the slope and y-intercept of the line 3x - 4y = 12?*

Lorico [155]

Answer:

m = 3/4; b = -3

Step-by-step explanation:

1) First, put the given equation into slope-intercept form. This is so we can identify its slope and y-intercept easily. Isolate y:

$3x-4y = 12\\-4y = -3x+12\\y = \frac{3}{4} x-3$

2) Lines that are in slope-intercept form are represented by the formula $y = mx + b$ . The number in place of $m$ , or the coefficient of the x-term, represents the slope. The number in place of $b$ represents the y-intercept. So, the slope of $y = \frac{3}{4} x-3$ is $\frac{3}{4}$ , and its y-intercept is -3.

5 0

3 years ago