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Wittaler [7]
3 years ago
14

Math homework please help

Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0
Y=1/5x-4 I hope this helps
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Find the 66th term of the arithmetic sequence -28,-45, -62,-
Alexeev081 [22]

Answer:

<u>-1133</u>

Step-by-step explanation:

<u>Formula for nth term</u>

  • aₙ = a + (n - 1)d

<u>Finding d</u>

  • d = -45 - (-28)
  • d = -45 + 28
  • d = -17

<u>Solving for a₆₆</u>

  • a₆₆ = -28 + 65(-17)
  • a₆₆ = -28 - 1105
  • a₆₆ = <u>-1133</u>
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2 years ago
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What is 600,000+80,000+10 in word form?
Juli2301 [7.4K]
Six hundred thousand plus eighty thousand plus ten
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3 years ago
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Solve for c, giving brainliest. please show your work/explain, i got to the point of square rooting 185, but i don't understand
Margarita [4]

Answer:

13.6 in

Step-by-step explanation:

Please refer to the attachment

6 0
3 years ago
When f(x)=4, what is the value of x?<br><br> 0<br> 2<br> 3<br> 4
BigorU [14]
The value of x in f(x)=4 is 4 because the f in f(x) is just 'naming' the equation, saying that x=a number, in this case, 4.
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4 years ago
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=
kenny6666 [7]

The cost to equip all the stations in the chemistry lab is calculated as: $393.75.

<h3>How to Calculate Total Cost?</h3>

In this scenario, we are given the following:

Total number of stations = 21 stations

Length of rubber tubing each of the stations in the chemistry lab needs = 5 feet

Total length of rubber tubing needed for all stations in the chemistry lab = 21 × 5 = 105 feet

Cost of 1 rubber tubing = $6.25 per yard

Convert 5 feet to yard:

1 yard = 3 feet

x yard = 5 feet

x = (5 × 1)/3

x = 5/3 feet.

So, the cost of 1 rubber tubing = $6.25 per 5/3

Cost of total length of tubbing needed = (105 × 6.25)/5/3 = (105 × 6.25) × 3/5

Cost of total length of tubbing needed = $393.75

Therefore, the cost to equip all the stations in the chemistry lab is calculated as: $393.75.

Learn more about the How to Calculate Total Cost on:

brainly.com/question/2021001

#SPJ1

6 0
2 years ago
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