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1 year ago

Find the 66th term of the arithmetic sequence -28,-45, -62,-

Mathematics

2 answers:

navik [9.2K]1 year ago

7 0

Answer:

-1133

Step-by-step explanation:

-17(66-1)+(-28)

-17(65)+(-28)

type in calculator or desmos

-1133

Alexeev081 [22]1 year ago

6 0

Answer:

-1133

Step-by-step explanation:

Formula for nth term

aₙ = a + (n - 1)d

Finding d

d = -45 - (-28)
d = -45 + 28
d = -17

Solving for a₆₆

a₆₆ = -28 + 65(-17)
a₆₆ = -28 - 1105
a₆₆ = -1133

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3 years ago

Rema purchased 18 ounces of gold in 2005 for $414 per ounce in order to try to diversify her investment portfolio. She sold a th

Licemer1 [7]

Given :

Rema purchased 18 ounces of gold in 2005 for $414 per ounce in order to try to diversify her investment portfolio.

She sold a third of her holdings in gold in 2009 at a price $953 per ounce. She sold the rest of her gold holdings in 2010 for $1,367 per ounce.

To Find :

What is Prema’s profit in 2009 and 2010.

Solution :

Price of one third ounces of gold, in 2005 is :

P = $414/3 = $138 .

Profit from selling them in 2009 is :

P1 = $(953 - 138) = $815 .

Profit from selling them in 2010 is :

P2 = $( 1367 - ( 414 - 138 ) ) = $1091 .

Therefore, Prema's profit in 2009 is $815 and 2010 is $1091.

Hence, this is the required solution.

5 0

2 years ago

The diameter of Circle terminates on the circumference of the circle at (3,0) and (3,−7).. Write the equation of the circle in

Verdich [7]

Step-by-step explanation:

that means the center of the circle is exactly in the middle between the 2 points.

and since both points have the same x value (so, the diameter here is a vertical line), it is ready to get the y value of the middle : (-7 - 0) / 2 = -3.5

so, the coordinates of the center are (3, -3.5).

and that makes the standard circle equation

(x - h)² + (y - k)² = r²

(x - 3)² + (y + 3.5)² = 3.5² = 12.25

as h, k are the coordinates of the center, and r is the radius (half the diameter).

7 0

2 years ago

4) The path of a satellite orbiting the earth causes it to pass directly over two

Naily [24]

Answers:

Satellite is approximately 2446.43 km from station A.
Satellite is approximately 2441.61 km above the ground.

=========================================================

Explanation:

I'm assuming tracking stations A and B are at the same elevation and are on flat ground. In reality, this is likely not the case; however, for the sake of simplicity, we'll assume this is the case.

The diagram is shown below. Points A and B describe the two stations, while point C is the satellite's location. Point D is on the ground directly below the satellite. We have these lengths

AB = 60 km
AD = x
CD = h

Focusing on triangle ACD, we can apply the tangent rule to isolate h.

tan(angle) = opposite/adjacent

tan(A) = CD/AD

tan(86.4) = h/x

x*tan(86.4) = h

h = x*tan(86.4)

We'll use this later in the substitution below.

--------------------

Now move onto triangle BCD. For the reference angle B = 85, we can use the tangent rule to say

tan(angle) = opposite/adjacent

tan(B) = CD/DB

tan(B) = CD/(DA+AB)

tan(85) = h/(x+60)

tan(85)*(x+60) = h

tan(85)*(x+60) = x*tan(86.4) ............. apply substitution; isolate x

x*tan(85)+60*tan(85) = x*tan(86.4)

60*tan(85) = x*tan(86.4)-x*tan(85)

60*tan(85) = x*(tan(86.4)-tan(85))

x*(tan(86.4)-tan(85)) = 60*tan(85)

x = 60*tan(85)/(tan(86.4)-tan(85))

x = 153.612786190499

--------------------

We'll use this approximate x value to find h

h = x*tan(86.4)

h = 153.612786190499*tan(86.4)

h = 2441.60531869599

h = 2441.61 km is how high the satellite is above the ground.

Return to triangle ACD. We'll use the cosine rule to determine the length of the hypotenuse AC

cos(angle) = adjacent/hypotenuse

cos(A) = AD/AC

cos(86.4) = x/AC

cos(86.4) = 153.612786190499/AC

AC*cos(86.4) = 153.612786190499

AC = 153.612786190499/cos(86.4)

AC = 2446.43279498247

AC = 2446.43 km is the distance from the satellite to station A.

6 0

3 years ago