Answer: the answer is <u><em>A</em></u>
- Explanation: Because bears know that every time they go for food near the picnic <u>they will find some</u> there
<u>Answer</u>:
- The possible genotypes of the children are Hh and hh.
- The probability of genotype Hh = 1/2
- The probability of genotype hh = 1/2
<u>Explanation</u>:
- <em>Autosomal genes</em> are the genes present on any of the chromosomes except the sex chromosomes.
- An autosomal recessive mutation is the mutation in an autosomal gene which only expresses itself in the phenotype in homozygous condition and affects both males and female equally.
- For the given question, let the autosomal gene be represented by H (dominant) and h (recessive)
- According to the question,
Since the <em>mother</em> is homozygous her genotype would be hh and the <em>father</em> is heterozygous so his genotype would be Hh.
The following cross is made to know the genotypes of the children :
hh X Hh--------> Hh Hh hh hh
So the <em>possible genotypes of the children are Hh and hh as shown in the cross. </em>
Note : An image is attached representing the cross in a Punnett square.
- The probability of an event = No. of favourable outcomes/total no. of outcomes
The probability of occurrence of genotype Hh would be = 2/4 = 1/2
Similarly, the probability of occurrence of genotype hh would be 2/4 = 1/2
Answer:
do they reproduce at all?
Explanation:
Answer:
1500
Explanation:
Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.
The total population size of F2 generation = 2000
The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)
Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500