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Inga [223]
3 years ago
14

☆Define kingdom monera???​

Biology
2 answers:
andreyandreev [35.5K]3 years ago
8 0

Monera is a kingdom that contains unicellular organisms with a prokaryotic cell organization, such as bacteria. They are single-celled organisms with no true nuclear membrane. The taxon Monera was first proposed as a phylum by Ernst Haeckel in 1866

BaLLatris [955]3 years ago
5 0

Answer:

monera is a kingdom that contains unicellular organisms with a prokaryotic cell organization ,such as bacteria .

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Answer: the answer is <u><em>A</em></u>

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A couple plans to have a child. the mother is homozygous for an autosomal recessive mutation. the father is heterozygous for the
adoni [48]

<u>Answer</u>:

  • The possible genotypes of the children are Hh and hh.
  • The probability of genotype Hh = 1/2
  • The probability of genotype hh = 1/2

<u>Explanation</u>:

  • <em>Autosomal genes</em> are the genes present on any of the chromosomes except the sex chromosomes.
  • An autosomal recessive mutation is the mutation in an autosomal gene which only expresses itself in the phenotype in homozygous condition and affects both males and female equally.
  • For the given question, let the autosomal gene be represented by H (dominant) and h (recessive)
  • According to the question,

Since the <em>mother</em> is homozygous her genotype would be hh and the <em>father</em> is heterozygous so his genotype would be Hh.

The following cross is made to know the genotypes of the children :

hh X Hh--------> Hh Hh hh hh

So the <em>possible genotypes of the children are Hh and hh as shown in the cross. </em>

Note : An image is attached representing the cross in a Punnett square.

  • The probability of an event = No. of favourable outcomes/total no. of outcomes

The probability of occurrence of genotype Hh would be = 2/4 = 1/2

Similarly, the probability of occurrence of genotype hh would be 2/4 = 1/2



3 0
3 years ago
Food passes along the GI tract in linear fashion, while the accessory organs are
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Answer B.

Explanation:

8 0
4 years ago
How do hydras reproduce????
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do they reproduce at all?

Explanation:

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You cross two true-breeding parents (one with yellow seeds and one with green seeds), grow and self-pollinate the F1 generation,
Andru [333]

Answer:

1500

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Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.

The total population size of F2 generation = 2000

The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)

Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500

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