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Tamiku [17]
3 years ago
13

For the function F defined by F(x) = x^2 – 2x + 4, find F(| – 4|).

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
7 0

| - 4 | = 4

Thus :

f ( | - 4 | ) = f ( 4 )

f ( 4 ) = ( 4 )^2 - 2(4) + 4

f ( 4 ) = 16 - 8 + 4

f ( 4 ) = 16 + 4 - 8

f ( 4 ) = 20 - 8

f ( 4 ) = 12

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What is the average rate of change of the function over the interval x = 0 to x = 8?<br>​
serious [3.7K]

Answer:

The average rate of change is:

\frac{13}{161}

Step-by-step explanation:

The rational function given to us is;

f(x)=\frac{3x+4}{2x+7}

f(0)=\frac{3(0)+4}{2(0)+7}

f(0)=\frac{4}{7}

f(8)=\frac{3(8)+4}{2(8)+7}

f(0)=\frac{28}{23}=1

The average rate of change of this function from x=0 to x=8  is the slope of the secant line connecting:

(0,f(0)) and (8,f(8))

Average rate of change ==\frac{f(8)-f(0)}{8-0}

=\frac{\frac{28}{23}-\frac{4}{7} }{8}

=\frac{13}{161}

7 0
3 years ago
The length of a rectangle is five centimeters less than width. Find the dimensions of the
kondaur [170]

Answer:

w is 10 and l is 5

Step-by-step explanation:

l=w-5

lw=50

w^2-5w-50=(w-10)(w+5) since the negative solution does not make sense w=10 and therefore l is 5 so the length is 5 while the width is 10

8 0
2 years ago
Lucas ate a fraction of a pizza. Hugo ate 5/8 of the same pizza. Now there is 1/8 of the pizza left what fraction of pizza did L
MatroZZZ [7]

Answer:

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Step-by-step explanation:

In order to solve this equation we will need to use what we know in order to find the answer.

1=\frac{8}{8}

H=\frac{5}{8}

R = \frac{1}{8}

If Huge ate 5/8's of the pizza and 8/8's creates a whole pizza then the question is quite simple. There is only 1/8's remaining after the boys finish their meal but 5/8's of the pizza was already eaten by Hugo meaning Lucas has to eat 2/8's of the pizza in order for there to be only 1/8's of the pizza left which means 2/8's is your answer.

Hope this helps.

5 0
3 years ago
Use the point-slope form, y - y1 = m(x - x1), to find the linear equation of a line that passes through the points
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3 years ago
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