Answer:
Step-by-step explanation:
(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3
(2^8 ⋅ 3^−5 ⋅ 6^0)^−6
(a^m)^n=a^m*n
So,
(2^8*-6) * (3^−5*-6) * (6^0*-6)
(2^-48) (3^30) (6^0)
a^0=1
So,
(2^-48) (3^30) (1)
<u>(2^-48) (3^30)</u>
I hope this helps you friend!
Answer:
40.5
Step-by-step explanation:
i multiplied 30 with .25 which was 7.5
then i multiplied 30 with .1 which was 3
add those together 10.5
add that too 30 which is 40.5
Answer:
a) √2
b) √(5a)
c) √3
d) -√2
e) -√(3x)
Step-by-step explanation:
This problem set makes use of the relation ...
... a√b = √(a²b)
a) (1/3)√18 = √(18·(1/3)²) = √(18/9) = √2
b) 5√(a/5) = √(25a/5) = √(5a)
c) 2√(3/4) = √(4·3/4) = √3
d) -10√0.02 = -√(100·0.02) = -√2
e) -(1/2)√(12x) = -√(12x/4) = -√(3x)
Answer:
x
y
−
1
−
1
0
0
Step-by-step explanation:
We are asked to solve for the zeros of the given quadratic equation f(x) = 9x2 + 6x + 1. To solve this, first, we need to set the given equation into zero such as the succeeding solution is shown below:
0 = 9x2 + 6x +1
Perform factoring such as:
0 = (3x + 1) (3x + 1)
Solving for x1, we have:
3x + 1=0
3x = -1
x1 = -1/3
Soving for x2, we have:
3x +1=0
x = -1/3
Therefore, the zeroes of the given expression is both -1/3 for x1 and x2.
