Let's say for example you wanted to graph the linear equation 
At minimum, we'll need 2 points to form this line.
To get any point of the form (x,y), we plug in a number for x to find a corresponding number for y.
For example, replace x with 0 to find that...
Therefore, x = 0 leads to y = 5. So the point (0,5) is on the line.
Then we repeat this process for other x values. Let's try x = 1
Telling us that (1,7) is also on this line. We have enough to graph this equation. Plot the two points (0,5) and (1,7). Then draw a straight line through them. Extend this line as far as you can to the left and right. The graph is shown below.
We can keep going to get other points like (2,9) and (3,11) and (4,13) and so on. A table is a way to keep track of the xy values.
Each time x goes up by 1, y goes up by 2. This directly ties to the slope of 2/1 = 2.
Answer:
31/40
Step-by-step explanation:
The question is incomplete. Here is the complete question with appropriate diagram.
The circle below has an area of 314 square centimeters, and the square inside the circle has a side length of 2 centimeters.
What is the probability that a point chosen at random is in the blue region?
Given the area of the circle to be 314cm², we need to get the diameter of the circle first since the diameter of the circle is equivalent to length of the side of the square inscribed in it.
Using the formula Area of a circle = πr²
314 = 3.14r²
r² = 314/3.14
r² = 100
r = 10 cm
Diameter of the circle = 2*10 = 20 cm
Area of a square = Length * length
Area of the outer square = 20*20 = 400cm²
Area of the inner square with side length 2cm = 2*2 =4cm²
Area of the shaded region = Area of the square - Area of the inner square
= 314-4 = 310cm²
The probability that a point chosen at random is in the blue region = Area of the shaded region/total area of the outer square
= 310/400
= 31/40
2.3 rounds to 2
because if the decimal is 5 or above you round up, if its less than 5 it stays the same. for example 2.6 round to 3 but 2.4 becomes 2
