-.1666667
You can use khan academy or Socratic if you still not sure.
Y=-1/2x-3
You can rewrite the equation “y=mx+b” and fill in what you know. So your equation would look like y=-1/2x+b when filling in what you know. Now you can take the (x,y) coordinates that you were given and plug them into the equation and solve for b. So now it would be -5=-1/2(4)+b
Step-by-step explanation:
pythagoras theorem: c²=a²+b²
Where c= longest side of a right angle triangle
AB= 6+r = c
AD= 12 =a
CD= r =b
(6+r)² = 12²+ r²
36+12r+r² =144 +r²
12r+r²-r²=144-36
12r=108
r= 108/12
r=9
Answer:
Option (1)
Step-by-step explanation:
x -2 -1 0 1 2
y 10 2.5 0 2.5 3.0
Ist difference,




= -2.5


= 2.5


= 7.5
2nd difference,


= 5


= 5


= 5
Since 2nd difference is common, given table represents a quadratic equation.
Let the equation is,
y = ax²+ bx + c
For a point (0, 0) passing through the quadratic equation,
0 = c
Therefore, quadratic equation is y = ax² + bx
Since ordered pair (-1, 2.5) passes through the graph of the function,
2.5 = a(-1)² + b(-1)
a - b = 2.5 ------(1)
For another point (1, 2.5)
2.5 = a(1)² + b(1)
a + b = 2.5 ------(2)
By adding equations (1) and (2),
2a = 5
a = 2.5
and from equation (2)→ y = 0
Therefore, equation of the quadratic function given in the table is y = 2.5x²
Option (1) is the answer.
I'm not I understand. The range is the highest value minus the lowest value, which on the graph is 10-4=6.