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Andrej [43]
2 years ago
14

-6 7/8 divided by (-3 3/4)

Mathematics
1 answer:
Nimfa-mama [501]2 years ago
4 0

Answer:

Exact Form: 11/6

Decimal Form: 1.83

Mixed Number Form: 1 5/6

Step-by-step explanation:

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Step-by-step explanation:

4 0
2 years ago
What fractions are in between -1/3 any -2/3
UNO [17]

To find a fraction between two fractions, all we need to do is make the sum of the numerators be the new numerator, and the sum of the denominators be the new denominator.(x) So, for example, a fraction between 7/13 and 6/11 is (7 + 6)/(13+ 11) =13/24.(x)

7/13 = .5384615(x)

6/11 = .545454(x)

13/24 = .541666�

 

Given that a/b < c/d, why is it true that a/b < (a+c)/(b+d)< c/d?

6 0
2 years ago
5) Out of a group of 40 students, 14 are taking English, 29 are taking Chemistry, and 5 are
Lostsunrise [7]

a. Venn diagram attached below.

b. 2 students are in neither English nor Chemistry.

c. The probability that a randomly chosen student is only taking chemistry is 24/40, or 6/10 because out of the 40 students, 24 of them take exclusively the chemistry class.

Download pdf
3 0
3 years ago
A line has a slope of 8 and a y -intercept of 5. What is its equation in slope -intercept form? Write your answer using integers
Dahasolnce [82]

Answer:

Step-by-step explanation:it’s abc

7 0
2 years ago
(25 points!!!!) draw the graph of the area bounded by these inequalities
Stels [109]

Step-by-step explanation:

To draw the graph, follow these steps:

  1. Graph the lines using points from the equations. (the blue line shown should be dotted, unfortunately I cannot do that in the program I used)
  2. Determine which direction the inequalities are correct.  
  3. Find the boundary given.

The three inequalities given form a triangle.

The first equation, y ≤ 2x + 5, has a y-intercept at (0, 5) and a point at (-2, 1).

The second equation, y < -3x + 10, has points at (3, 1) and (2, 4).

Use two points to draw the lines.

After the lines are drawn, determine which side of the line the inequality works on. You can do this by testing points that are not on the line.

I will test each inequality using (0, 1):

y ≤ 2x + 5

0 ≤ 2 + 5

<em>This is correct</em>, so the inequality for y ≤ 2x + 5 will be shaded towards (0, 1).

y < -3x + 10

0 < -3 + 10

<em>This is correct,</em> so the inequality for y < -3x + 10 will be shaded towards (0, 1).

0 ≤ 1

<em>This is correct</em>, so the inequality for 0 ≤ y will be shaded upwards towards (0, 1).

The end result of this graph is all three inequalities being shaded (inwards).

The solution is a triangle with points at (1, 7), (3.33333, 0), and (-2.5, 0).

3 0
3 years ago
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