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konstantin123 [22]
3 years ago
8

HELP I NEED SOMBODEY HELP NOT JUST ANYONE JK HELP ME PLSSSSS

Mathematics
1 answer:
tatuchka [14]3 years ago
8 0
You cross multiply/butterfly method so 5•6= 30 and 5•8=40 so it would be 30/40 OR 3/4 simplified
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Solve each equation. check your solution. <br> -1/2x-7=-11
cupoosta [38]
I'll offer you a deal in return for your 5 points:  I'll solve it . . . . You check it.

<u>-1/2x - 7  = -11</u>

Add  7  to each side:            -1/2 x  =  -4

Multiply each side by  2 :      - x  =  -8

Multiply each side by  -1 :     <em> x  =  8</em>

Take it Allalala !

4 0
3 years ago
Read 2 more answers
Which angles are adjacent gbm and fbc or cbx and fbc or xbg and fbc or mby and fbc
Natalija [7]

Answer:

CBX and FBC

Step-by-step explanation:

adjacent angles are right next to each other

7 0
3 years ago
Delta math help plz im stuck
JulsSmile [24]

Step-by-step explanation:

-70x^4 + 30x

= 10x(-7x^3 + 3)

ANSWER: 10x(-7x^3 + 3)

3 0
3 years ago
What is the value of the expression 2x3y when x= −2 and y = 3?
klemol [59]
I think it’s -36, not 100% sure though
6 0
3 years ago
A school fair ticket costs $8 per adult and $1 per child. On a certain day, the total number of adults (a) and children (c) who
gtnhenbr [62]

Let a be the number of adults which bought a ticket and c the number of children who bought a ticket. We can use the information given to assemble a system of equations.

Tickets cost 8 dollars for a, 1 dollar for c, and the total amount made is 100

8a + c = 100

The total of a and c is 30

a + c = 30

We can now subtract one equation from the other to use the elimination method to solve the system.

8a + c = 100

-(a + c = 30)

7a + 0 = 70

We can now solve for a.

7a = 70

a = 10

There were 10 adults who bought tickets. We can use this value as a known, plugging it into an equation to solve for the number of children.

a + c = 30

10 + c = 30

c = 20

So, the final answer is "20 children and 10 adults Equation 1: a + c = 30 Equation 2: 8a + c = 100".

6 0
3 years ago
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