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konstantin123 [22]
3 years ago
8

HELP I NEED SOMBODEY HELP NOT JUST ANYONE JK HELP ME PLSSSSS

Mathematics
1 answer:
tatuchka [14]3 years ago
8 0
You cross multiply/butterfly method so 5•6= 30 and 5•8=40 so it would be 30/40 OR 3/4 simplified
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Eathan correctly answers 80% of the total questons
KATRIN_1 [288]

Answer:

he got 20% wrong

he got a B

Step-by-step explanation:

3 0
3 years ago
Please help me find the slope intercept form plesseeeeeee
Vitek1552 [10]

Answer: y = (-1/2)x + 2

Step-by-step explanation:

6 0
3 years ago
You have two exponential functions. One has the formula h(x) = 2 x + 3. The other function, g(x), has the graph shown below.
Alex17521 [72]
To answer, we substitute each of the numbers in parentheses to x of h(x) and get the value of g(x).

A. h(2) = 2(2) + 3 = 7  ;   g(2) < 4               (neither is equal to 7)

B. h(7) = 2(7) + 3 = 17;    g(7) is not shown in the graph          (not true)

C. h(2) = 7   ; g(2) < 4   Thus, g(2) < h(2)   (choice is not true)

D. From C, g(2) < h(2)   (TRUE)

Thus, the answer to this item is letter D. 
5 0
3 years ago
Read 2 more answers
The hypotenuese of an isosceles right triangle is 16 inches. The midpoints of its sides are connected to form an inscribed trian
ser-zykov [4K]

Answer:

  256/3 = 85 1/3 square inches

Step-by-step explanation:

The dimensions of the first inscribed triangle are 1/2 those of the original, so its area is (1/2)² = 1/4 of the original. The area of the original is ...

  A = (1/2)bh = (1/2)(16/√2)(16/√2) = 64 . . . . square inches

The sum of an infinite series with first term 64 and common ratio 1/4 is ...

  S = a1/(1 -r) . . . . . . for first term a1 and common ratio r

  = 64/(1 -1/4) = 64(4/3) = 256/3 . . . . square inches

The sum of the areas of the triangles is 256/3 = 85 1/3 square inches.

3 0
4 years ago
What is the mass of a solid ball of iron with a radius equal to 18 cm if it is known that the density of iron is 7800 kg/m
Shtirlitz [24]

Answer:

60.6528 kg

Step-by-step explanation:

Assuming the solid ball of iron is a sphere with a radius of 18 cm (or 0.18 m), we can compute the volume of the sphere:

V=\frac{4}{3}\pi r^3\\\\V=\frac{4}{3}\pi (\frac{18}{100})^3\\\\V=\frac{4}{3}\pi (0.005832)\\\\V=0.007776

Therefore, the volume of the solid ball is 0.007776 m³

Since we know that density is mass/volume, then we can find the mass of the iron:

\rho=\frac{mass}{volume}\\ \\7800\: kg/m^3=\frac{mass}{0.007776\: m^3}\\\\mass=60.6528\:kg

Thus, the mass of the solid ball of iron is 60.6528 kg

8 0
3 years ago
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