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3 years ago

What is the value of the expression 2x3y when x= −2 and y = 3?

Mathematics

1 answer:

klemol [59]3 years ago

6 0

I think it’s -36, not 100% sure though

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Lily works at a company that makes shirts by hand. She recorded the number of shirts (y) each of eight employees made in one day

inn [45]

Your answer is B because in order for it to be a scatter plot it has to have 2 points going through the line

7 0

3 years ago

How many ways can a committee of 6 be selected from a club with 10 members

Ratling [72]

Answer:

210

Step-by-step explanation:

The general formula for picking k items from a total of n is

$_{n}C_{k} = \frac{n! }{(n-k)!k! }$

Thus, if we want to select a committee of six people from a club with 10 members, the number of combinations is

$_{10}C_{6} = \frac{10! }{(10-6)!6! }$

$= \frac{10! }{4!6! }$

$= \frac{10\times9\times8\times7}{4\times3\times2\times1 }$

$= \frac{5040 }{24 }$

= 210

The committee can be selected in 210 separate ways.

4 0

3 years ago

How many times does 3/4 go into 4.5

SpyIntel [72]

Answer:

6 times

Step-by-step explanation:

Turn that fraction into a decimal. 3/4=0.75

Divide!

4.5/0.75=6

3 0

4 years ago

Read 2 more answers

What times 3 equals something that is divisible by 2 that equals 8?

Delicious77 [7]

Let the unknown be n, then: n × 3 = 8 × 2 n × 3 = 16 n = 16 ÷ 3 n = 5.333

8 0

3 years ago

Let R be the region in the first quadrant bounded by the graphs of y =x^2 and y=2x, as shown in the figure above. The region R i

Kobotan [32]

Answer:

The area between the two functions is approximately 1.333 units.

Step-by-step explanation:

If I understand your question correctly, you're looking for the area surrounded by the the line y = 2x and the parabola y = x², (as shown in the attached image).

To do this, we just need to take the integral of y = x², and subtract that from the area under y = 2x, within that range.

First we need to find where they intersect:

2x = x²

2 = x

So they intersect at (2, 4) and (0, 0)

Now we simply need to take the integrals of each, subtracting the parabola from the line (as the parabola will have lower values in that range):

$a = \int\limits^2_0 {2x} \, dx - \int\limits^2_0 {x^2} \, dx\\\\a = x^2\left \{ {{x=2} \atop {x=0}} \right - \frac{x^3}{3}\left \{ {{x=2} \atop {x=0}} \right\\\\a = (2^2 - 0^2) - (\frac{2^3}{3} - \frac{0^3}{3})\\\\a = 2^2 - \frac{2^3}{3}\\a = 4 - 8/3\\a \approx 1.333$

So the correct answer is C, the area between the two functions is 4/3 units.

3 0

3 years ago