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Sever21 [200]
3 years ago
10

In the right-angled triangle abc,ac is the hypotenuse with length 8cm, and ab=6 cm.

Mathematics
1 answer:
faltersainse [42]3 years ago
7 0

Answer:

Step-by-step explanation:

Hypotenuse = AC = 8 cm

AB = 6 cm

 BC² + AB² = AC²

BC² = AC² - AB²

       = 8² - 6²

       = 64 - 36

       = 28

BC =\sqrt{28}=\sqrt{2*2*7}=2\sqrt{7} = 2*2.6458 =5.2916 = 5.29

BC = 5.29 cm

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Bezzdna [24]
30043——————3.0043 x 10^4
30.043—————— 3.0043 x10^1
0.0030043—————-3.0043 x 10^-3
0.30043—————-3.0043 x 10^-1
3.0043————-3.0043 x 10^0

Hope this helps please mark brainiest
8 0
3 years ago
Find the total cost to the nearest cent.<br> $49.95 pair of shoes; 5% tax
Nana76 [90]

Answer:

$52.45

Step-by-step explanation:

the tax is $2.50, if we add that to $49.95 we get $52.45

5 0
3 years ago
What minus 1/2 equals 3/4
dimaraw [331]

Answer:

W =1 1/4Step-by-step explanation:

Let W = what

W - 1/2 = 3/4

Add 1/2 to each side

W -1/2 +1/2 = 3/4+1/2

W = 3/4+1/2

Getting a common denominator of 4

W =3/4+1/2*2/2

W =3/4 +2/4

W = 5/4

Changing to a mixed number

W = 4/4 +1/4

W = 1 +1/4

W =1 1/4

6 0
4 years ago
When constructing parallel lines, how can you verify the lines constructed are parallel? Check the intersecting lines with the c
Bond [772]

Answer:

Check the distance between the lines at several places with a compass to ensure they are equidistant.

Step-by-step explanation:

The distance between the parallel lines is always constant and they never intersect with each other.

So, to verify if the lines constructed are parallel, we can check the following:

Check the distance between the lines at several places with a compass to ensure they are equidistant.

6 0
4 years ago
Please HELPPPP me !!!!!
dedylja [7]

Answer:

y = 4x - 3\\Slope \ m_1 = 4

EQUATION OF LINE PERPENDICULAR

Lines \ are \  perpendicular => m_1 \cdot m_2 = -1\\

slope, m_2 = \frac{-1}{4}

equation \ of \ the\ line \ passing \ through \ (-2, 2) \ slope ,m_2 :\\(y - y_2) =m_2(x - x_2)\\ (y - 2) = \frac{-1}{4} (x -(-2))\\\\y - 2 = \frac{-1}{4} (x +2)\\\\y = \frac{-1}{4}x - \frac{1}{2}  + 2\\\\y = \frac{-1}{4}x + \frac{3}{2}

EQUATION OF LINE PARALLEL

Lines \ are \ parallel => m_1 \cdot m_3 = 1\\slope, m_3 = \frac{1}{4}Equation \ of \ the \ line \ through \ (-2, 2) \ and \ slope, m_3:\\(y - y_3) =m_3(x - x_3)\\\\(y-2) = \frac{1}{4} (x - (-2))\\\\y-2 = \frac{1}{4}(x+2)\\\\y = \frac{1}{4}x + \frac{1}{2} +2\\\\y = \frac{1}{4}x + \frac{5}{2}

6 0
3 years ago
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