Answer:
Hence the area of each of the triangles are:
49 cm^2 and 16 cm^2.
Step-by-step explanation:
If the two triangles are similar; the perimeters of the two triangles are in the same ratio as the sides.
We are given that the ratio of the perimeters of two similar triangles is 4:7.
Let a and b denotes perimeter of two triangles.
i.e. here a:b=4:7.
Let A and B denote the area of two triangles.
also we know that for two similar triangles;
Hence,
Also the sum of their areas is 65 cm^2.
i.e.
on putting equation (2) in equation (1) we have:
49(65-B)=16B
49×65-49B=16B
49×65=49B+16B
49×65=65B
B=49 cm^2
Hence by equation (2) we have:
A=65-B
A=65-49=16 cm^2.
Hence the area of each of the triangles are:
49 cm^2 and 16 cm^2.
Answer:
12.75
Step-by-step explanation:
c = π x d
40.035= 3.14 x d
40.035/3.14 = 12.75
61.4⋅2=x
x=122.8
hope this helps!
To solve this problem, the first thing we have to do is regroup the terms so that we can then subtract, simplify, subtract, and finally simplify again.
But first we must know.
<h3>¿What are the equations?</h3>
Equations are those mathematical equalities divided between two expressions which are called members and separated by their equal sign, in which known elements and unknown or unknown data appear, related by mathematical operations.
<h3>We solve the problem:</h3>
- 8n - 7 = -12 + 3n
- 8n - 7 = 3n - 12
- 8n - 7 - 3n = -12
- 5n - 7 = -12
- 5n = -12 + 7
- 5n = -5
- N = -1
Now we must check our results.
8n -7 = -12 + 3n
8 × - 1 - 7 = -12 + 3 × - 1
- 8 - 7 = - 12 - 3
- 15 = - 12 - 3
- 15 = - 15
So, our results are correct, the answer is n = - 1
¡Hope this helped!