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3 years ago

I need help with the top part

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

5 0

Answer:

1. (1, 2)

2. (-5, 7)

3. (-6, -5)

4. (0, -3)

Step-by-step explanation:

(1 - 4) Explanation:

If we're asked to move to the right, make the x-coordinate a positive number.

If we're asked to move to the left, make the x-coordinate a negative number.

If we're asked to move upwards, make the y-coordinate a positive number.

If we're asked to move downwards, make the y-coordinate a negative number.

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Pentagon A is rotated 180° about its center and then translated to create pentagon B.

liubo4ka [24]

The value of x after the simultaneous rotation and translation of pentagon A to create pentagon B is 110°

<h3>What is the translation of plane figures?</h3>

A plane figure translation is an isometry that translates each position of the figure at a distance and in a direction indicated by the vector.

It is also regarded as a sort of transformation that involves sliding each point in a plane figure at an identical distance in a similar direction.

From the attached image, the value of x after the simultaneous rotation and translation of pentagon A to create pentagon B is 110°.

Learn more about the translation of plane figures here:

brainly.com/question/2467920

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2 years ago

Evaluate lim x → 0+ x ln(x3). solution the given limit is indeterminate because, as x → 0+, the first factor (x) approaches 0 co

Degger [83]

$\displaystyle\lim_{x\to0^+}x\ln x^3=\lim_{x\to\infty}\frac{\ln\frac1{x^3}}x=-3\lim_{x\to\infty}\frac{\ln x}x=\frac\infty\infty$

L'Hopital's rule tells us the limit is equal to

$-3\displaystyle\lim_{x\to\infty}\frac{\frac1x}1=0$

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4 years ago

A suitcase has a lock on it consisting of four numbers. Each number could be any number 0-9. The only restriction is that the la

photoshop1234 [79]

Answer: We have 5000 possible combinations.

Step-by-step explanation:

I guess that we want to find the possible combinations for this lock.

We have 4 numbers, so we have 4 selections.

Now, let's count the number of options in each selection.

in the first selection, we have 10 options (0, 1, 2, 3, 4, 5, 6, 7, 8 and 9)

in the second selection, we have 10 options (0, 1, 2, 3, 4, 5, 6, 7, 8 and 9)

in the third selection, we have 10 options (0, 1, 2, 3, 4, 5, 6, 7, 8 and 9)

in the last selection, we have 5 options (0, 2, 4, 6 and 8)

The total number of combinations is equal to the product of the number of options in each selection:

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3 years ago

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Julli [10]

I think it is 3 maybe

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3 years ago

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