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Harman [31]
3 years ago
9

Solve for x. 3x/6 + 2 = 8

Mathematics
2 answers:
Black_prince [1.1K]3 years ago
6 0

Answer:

x=12

Step-by-step explanation:

3x/6 + 2 = 8

Subtract 2 from each side

3x/6 + 2-2 = 8-2

3x/6 =6

Multiply each side by 6/3

6/3 * 3/6 x = 6 *6/3

x = 36/3

x = 12

Mnenie [13.5K]3 years ago
3 0

\large\bf{{\red{ \longrightarrow \:\large\rm{{\blue{ \frac{3x}{6} \:  +  \: 2 \:  =  \: 8 }}} }}} \\

\large\bf{{\red{ \longrightarrow \:\large\rm{{\blue{ \frac{3x}{6} \:   =  \: 8 \:  -  \: 2 }}} }}} \\

\large\bf{{\red{ \longrightarrow \:\large\rm{{\blue{ \frac{3x}{6} \:   =  \: 6 }}} }}} \\

\large\bf{{\red{ \longrightarrow \:\large\rm{{\blue{  \frac{3x}{6}  \:  +  \: 6}}} }}} \\

\large\bf{{\red{ \longrightarrow \:\large\rm{{\blue{  \frac{3x \:  +  \: 36}{6}  \:}}} }}} \\

\large\bf{{\red{ \longrightarrow \:\large\rm{{\blue{  \frac{3x \:  +  \:  \cancel{36}  \:  \: ^{6} }{ \cancel6}  \:}}} }}} \\

\large\bf{{\red{ \longrightarrow \:\large\rm{{\blue{  \: x \:  =  \:  \frac{36}{6}  }}} }}} \\

\large\bf{{\red{ \longrightarrow \:\large\rm{{\blue{  \: x \:  =  \:   \cancel\frac{{36}{   \: ^{6} }} {6}  }}} }}} \\

\large\bf{{\red{ \longrightarrow \:\large\rm{{\blue{  \: x \:  =  \:  6 }}} }}} \\

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<span />
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What is the value ofx in the equation 2(6x+4)-6+2x=3(4x+3) + 1<br> 1<br> 3<br> 4<br> 6
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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Equality Properties
  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define Equation</u>

2(6x + 4) - 6 + 2x = 3(4x + 3) + 1

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute:                                   12x + 8 - 6 + 2x = 12x + 9 + 1
  2. Combine like terms:                   14x + 2 = 12x + 10
  3. Subtract 12x on both sides:       2x + 2 = 10
  4. Subtract 2 on both sides:          2x = 8
  5. Divide 2 on both sides:              x = 4
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3 years ago
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Answer:

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