(8z - 10) ÷ (-2) + 5(z - 1) = 8z - 10 ÷ -2 + 5z - 5 = 8z + 5 + 5z - 5 = 13z
Let's say the first number is "a"
the next consecutive can just be "a+1" and the next, you guessed it, "a+2"
the two smaller ones are a and a+1, the larger one is a+2
now, the product of "a" and "a+1" equals 5 times "a+2" but less by 5
thus a(a + 1) = 5(a + 2) - 5 <----- solve for "a"
Answer:
.15 percent
Step-by-step explanation:
I just divided 3 by 19 and set them equivalent to each other.