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3 years ago

Pre cal/cal master needed

1 answer:

5 0

Take x-2 and insert it into 2x^2 + 3x-2 where the x is located
2x^2 + 3x-2
2(x-2)^2 + 3(x-2)-2

Now work out 2(x-2)^2 + 3(x-2)-2 also follow PEMDAS
2(x-2)^2 + 3(x-2)-2
Since (x-2)^2 is an Exponent, lets work with that first and expand (x-2)^2.
(x-2)^2
(x -2)(x-2)
x^2 -4x + 4
Now Multiply that by 2 because we have that in 2(x-2)^2
(x-2)^2 = x^2 -4x + 4
2(x-2)^2 = 2(x^2 -4x + 4)
2(x^2 -4x + 4) = 2x^2 - 8x + 8
2x^2 - 8x + 8

Now that 2(x-2)^2 is done lets move on to 3(x-2).

Use the distributive property and distribute the 3
3(x-2) = 3x - 6

All that is left is the -2

Now lets put it all together
2(x-2)^2 + 3(x-2)-2

2x^2 - 8x + 8 + 3x - 6 - 2

Now combine all our like terms
2x^2 - 8x + 8 + 3x - 6 - 2
Combine: 2x^2 = 2x^2
Combine: -8x + 3x = -5x
Combine: 8 - 6 - 2 = 0

So all we have left is
2x^2 - 5x

Read more about LaGrange multiplier

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8 0

2 years ago

There were five teams entered in a competition. Each team consisted of either only boys or only girls. The number of team member

WINSTONCH [101]

Answer:

21.

Step-by-step explanation:

Since there were five teams entered in a competition, and each team consisted of either only boys or only girls, with the number of team members being 9, 15, 17, 19 and 21 members, if after one team of girls had been knocked out of the competition, the number of girls still competing was three times the number of boys, to determine how many girls were in the team that was eliminated, the following calculation must be performed:

9 + 15 + 17 + 19 = 60/4 = 15

9 + 15 + 17 + 21 = 62/4 = 15.5

9 + 15 + 19 + 21 = 64/4 = 16

9 + 17 + 19 + 21 = 66/4 = 16.5

15 + 17 + 19 + 21 = 72/4 = 18

Thus, since 15 x 3 equals 45, and 45 plus 15 equals 60, the number of girls on the team that was eliminated was 21.

3 0

3 years ago

Can you help me with this problem 5 divided by 0.8 work this out

Alisiya [41]

To make it easy we can multiply 5 and 0.8 times 10 before we start dividing. The result will no change because we multiplying both numbers by the same number.
5*10=50
0.8*10=8
No we can divide 50:8
6,25 - its the result
50:8
48
20
16
40
40
0

Hope that helps.

7 0

3 years ago

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Using the distance formula , find the distance from the center of your habitat to the point (x, y). Write this equation. Your an

alexdok [17]

Answer:

See explanation

Step-by-step explanation:

The distance formula is given by:

$d = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

We want to find the distance between (a,b) and (x,y).

The center of the habitat is missing in the question.

Assuming the center is (a,b) where a and b are real numbers, then we can use the distance formula to obtain:

$d = \sqrt{(x - a)^{2} + {(y - b)}^{2} }$

For instance if the center of your habitat us (2,-1), then

$d = \sqrt{(x - 2)^{2} + {(y + 1)}^{2} }$

6 0

3 years ago

An ellipse has a center at the origin, a vertex along the major axis at (20, 0), and a focus at (16, 0). the equation of the ell

olga_2 [115]

If the center is at (0, 0) and the vertex is at (20, 0), then the distance, a, is the length from the center to the vertex, 20. The distance from the center to the focus is c. The distance from the center to the focus is 16, so c = 16. The formula we use to find the focus is $c^2=a^2-b^2$ . We have our c value and our a value, so we will sub in those to find b. $16^2=20^2-b^2$ and 256 = 400 - b^2. -b^2 = -144, so b = 12. There you go!

5 0

3 years ago

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