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Lerok [7]
3 years ago
12

Divide 71/9 2/34 A. 21/4 B. 23/4C. 41/4D. 413/16HELLPPPPPP ​

Mathematics
1 answer:
ozzi3 years ago
8 0

Answer:

A 5.25, B 5.75, C 10.25, D 25.8125

Step-by-step explanation:

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A 35-foot tall pole is leading towards a building. To stop the pole from leaning
Lapatulllka [165]

9514 1404 393

Answer:

  38.5°

Step-by-step explanation:

You are given all three side lengths of the relevant triangle, so the Law of Cosines can be used to find any desired angle. If we call the desired angle C, then that law tells you ...

  C = arccos((a² +b² -c²)/(2ab))

where a and b are the triangle side lengths adjacent to the angle of interest, and c is the side opposite. Here, 'a' and 'b' are the pole and cable lengths, and 'c' is the distance of the stake from the pole.

  C = arccos((35² +48² -30²)/(2·35·48)) = arccos(2629/3360)

  C ≈ 38.515°

The cable makes an angle of about 38.5° with the pole.

5 0
3 years ago
PLEASE HELP ME ASAP!!!! Can you calculate problems involving percent?
ella [17]

Answer: Yes.

Step-by-step explanation: Convert it to a decimal. Percent means per 100. So if you have 50% the decimal form is .5 since you divide 50 by 100. 5% would be .05 etc

6 0
3 years ago
Read 2 more answers
Translate this phrase into an algebraic expression.
Tems11 [23]

Answer:

2v + 20

Step-by-step explanation:

Hey!

3 0
3 years ago
On a basketball court the free throw line is marked off geometrically this area of the court is called a key and is topped
Alenkinab [10]

Step-by-step explanation:

Arc length formula is

s = rx

where x is radinas.

A semi circle has a radian measure of

\pi

The radius is half of the diameter, 12 so the radius is

12 \times  \frac{1}{2}  = 6

So the arc length is

6 \times \pi = 6\pi

Area of semi circle is

\frac{1}{2} \pi {r}^{2}

where r is the radius.

\frac{1}{2} \pi6 {}^{2}

\frac{1}{2} 36\pi

18\pi

3 0
2 years ago
What is the reminder when (3x^3-2x^2+4x-3) is divided by (x^2+3x+3)
NARA [144]
(For full answer you might have to go to the comments)

Answer: 28x+30

Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
___________________
(x^2+3x+3) 3x^3-2x^2+4x-3


-(3x^3+9x^2+9x)
__________________

-11x^2-5x-3

-(-11x^2-33x-33)
____________
28x+30

So our remainder will be 28x+30
5 0
3 years ago
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