Expanding the limit, we get (x^2+2x∆x+∆x^2-2x-2∆x+1-x^2+2x-1)/<span>∆x
Crossing the 1s , the 2xs, and the x^2s out, we get
(2x</span>∆x+∆x^2-2∆x)/<span>∆x
Dividing the </span><span>∆x, we get
2x+</span><span>∆x-2.
Making the limit of </span><span>∆x=0, we get 2x-2.</span>
Answer/Step-by-step explanation:
To find out the mistake of the student, let's find the min, max, median, Q1 and Q3, which make up the 5 important values that are represented in a box plot.
Given, {2, 3, 5, 6, 10, 14, 15},
Minimum value = 2
Median = middle data point = 6
Q1 = 3 (the middle value of the lower part of the data set before the median)
Q3 = 14 (middle value of the upper part of the data set after the median)
Maximum value = 15
If we examine the diagram the student created, you will observe that he plotted the median wrongly. The median, which is represented by the vertical line that divides the box, ought to be at 6 NOT 10.
See the attachment below for the correct box plot.
Answer:
<u>(2) x </u>
<u> 4</u>
Step-by-step explanation:
Given the sqrt(x), x
zero
So, given sqrt(x -4), x -4
0
Now solve for x
x - 4
0
x
4
Answer:
A. 9.18 x 
B.12002
Step-by-step explanation:
To calculate the speed, divide 15.75 by 2.25 and you get 7 mph.