All categories

2 years ago

Which table best represents the system of equations below. y=x-4 y=(2x-17)

Mathematics

1 answer:

vekshin12 years ago

6 0

Answer:

To make a table u need to have coordinates, (x, y).

Solve for them using substitution:

y = x - 4 ↔ x = y + 4

y = (2x - 17)

PLUG IN TO y = (2x - 17).

y = (2(y+4) - 17)

Solve for y:

y = 2y + 8 - 17

y = 2y - 9

-1y = -9

y = 9

Solve for x:

x = (9) + 4

x = 13

Keep solving for x and y to have your coordinates for your table.

You might be interested in

Needing some help on this cuz nobody else knows

sashaice [31]

There’s no pictures/angles to this?

8 0

2 years ago

What's a Hypotnuse and adjacent?

miss Akunina [59]

Its very simple. You see, consider a right angled triangle, and the side opposite to the right angle or the largest side is Hypotnuse and the side the is adjacent to the angle that you choose is the adjacent side.

4 0

2 years ago

Read 2 more answers

Can anyone explain what Literal Equations are? PLZ.

melisa1 [442]

Answer:

A literal equation is an equation that consists of multiple variables or letters.

A linear equation is an equation that consists of one variable

Step-by-step explanation:

Literal EX:

a = 1/2h(a + b)

ax + b = c

u = ak/b

Linear EX:

5(3a + 8) = 12a

4a = 8

11(3a - 18) = 12a

4 0

2 years ago

Read 2 more answers

How can sample data be used to from an estimate about the population?

dsp73

Answer: A proportion can be solved to relate the sample to the population and solved to form an estimate.

Step-by-step explanation:

4 0

2 years ago

A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use of one particular cust

Fiesta28 [93]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given set of values

$321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320$

STEP 2: Write the formula for calculating the Standard deviation of a set of numbers

$\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ where\text{ }x_i\text{ are data points,} \\ \bar{x}\text{ is the mean} \\ \text{n is the number of values in the data set} \end{gathered}$

STEP 3: Calculate the mean

$\begin{gathered} \bar{x}=\frac{\sum ^{}_{}x_i}{n} \\ \bar{x}=\frac{\sum ^{}_{}(321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320)}{20} \\ \bar{x}=\frac{8453}{20}=422.65 \end{gathered}$

STEP 4: Calculate the Standard deviation

$\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ \sum ^{}_{}(x_i-\bar{x})^2\Rightarrow\text{Sum of squares of differences} \\ \Rightarrow10332.7225+657.9225+18591.3225+982.8225+2740.52251+9731.8225+3522.4225+18319.6225+2878.3225 \\ +8163.1225+1417.5225+3925.0225+1321.3225+386.1225+5677.6225+2953.9225+3800.7225 \\ +3209.2225+2565.4225+10537.0225 \\ \text{Sum}\Rightarrow108974.0275 \\ \\ S\tan dard\text{ deviation}=\sqrt[]{\frac{111714.55}{20-1}}=\sqrt[]{\frac{111714.55}{19}} \\ \Rightarrow\sqrt[]{5879.713158}=76.67928767 \\ \\ S\tan dard\text{ deviation}\approx76.68 \end{gathered}$

Hence, the standard deviation of the given set of numbers is approximately 76.68 to 2 decimal places.

STEP 5: Calculate the First and third quartile

$\begin{gathered} \text{IQR}=Q_3-Q_1 \\ \\ To\text{ get }Q_1 \\ We\text{ first arrange the data in ascending order} \\ \mathrm{Arrange\: the\: terms\: in\: ascending\: order} \\ 320,\: 321,\: 324,\: 360,\: 361,\: 366,\: 369,\: 372,\: 385,\: 397,\: 403,\: 454,\: 459,\: 475,\: 477,\: 482,\: 498,\: 513,\: 558,\: 559 \\ Q_1=(\frac{n+1}{4})th \\ Q_1=(\frac{20+1}{4})th=\frac{21}{4}th=5.25th\Rightarrow\frac{361+366}{2}=\frac{727}{2}=363.5 \\ \\ To\text{ get }Q_3 \\ Q_3=(\frac{3(n+1)}{4})th=\frac{3\times21}{4}=\frac{63}{4}=15.75th\Rightarrow\frac{477+482}{2}=\frac{959}{2}=479.5 \end{gathered}$

STEP 6: Find the Interquartile Range

$\begin{gathered} IQR=Q_3-Q_1 \\ \text{IQR}=479.5-363.5 \\ \text{IQR}=116 \end{gathered}$

Hence, the interquartile range of the data is 116

3 0

9 months ago