Question

The cruising speed of a 747 airplane is approximately 9,944 inches per second. What is this speed to the nearest foot per second?

Answer 1

For this case, the first thing we must do is take into account the following conversion factor:

$1 \ ft = 12\ inches$

Therefore, by applying the conversion factor for the given velocity we have:

$(9944 \frac {in} {s}) (\frac {1} {12} \frac {ft} {in}) = 829 \frac {ft} {s}$

Answer:

The speed of the plane in foot per second is given by:

$829 \frac {ft} {s}$

Answer 2

828.6 repeating  (or 829 rounded up) feet per second.