The equation of the line in point-slope form is: C. y − 5 = −(x − 2).
<h3>What is the Point-Slope Equation of a Line?</h3>
A line with a slope (m) and a point (a, b) is represented in point-slope form as, y - b = m(x - a).
Slopes of perpendicular lines are negative reciprocals of each other. Find the slope of the line in the graph given as follows:
Slope (m) = rise/run = 3 units/3 units = 1
Negative reciprocal of 1 is -1.
The slope of the line would be m = -1.
Substitute m = -1 and (a, b) = (2, 5) into y - b = m(x - a) to wrote the equation:
y - 5 = -1(x - 2)
y − 5 = −(x − 2)
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Answer:
120 On edge i got it right
Step-by-step explanation:
Answer:
y=-3x+1
Step-by-step explanation:
plug in point into x and y, replace -4 as a +b(or any other variable to represent y intercept)
therefore,
7=-3(-2)+b
7=6+b
1=b
y=-3x+1
3x + 20 = 5x - 16
3x - 5x = -16 - 20
-2x = -36
x = -36/-2
x = 18
The measure of angle xyz can also be said to be the measure of angle y.
So, y = (3•18 + 20)
y = 54 + 20
y = 74°
The measure of angle xyz = 74°.