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Oksi-84 [34.3K]
3 years ago
7

3. 8x + 4y24 and 6x + 6y = 6​

Mathematics
1 answer:
anzhelika [568]3 years ago
5 0

Answer:

x and y

Step-by-step explanation:

Variables are always the numbers that're replaced with a letter. For example, in the equation:

2t+6

t would be the variable.

Hope this helps!! <3 :)

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Negation of all owls fly?
Reptile [31]
Looking at this in terms of sets, let's call O the set of all owls, and F the set of all things that can fly. What this original statement is saying every animal that's a member of the set of all owls is also a member of the set of all things that can fly, or in other words, O⊂F (O is a subset of F). Negating this tells us that, while there's <em>at least one</em> element of O that also belongs to F, O is not contained entirely in F (O⊆F, in notation), so a good negation or our original statement might be:

<em>Not all owls can fly.</em>
8 0
3 years ago
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Which of the following is true with respect to the following functions
valina [46]

Answer:

your answer is c

Step-by-step explanation:

I kiss my grandma on the butt lumps

3 0
3 years ago
Ratio in simplest form 8 pounds to 10 pounds
FinnZ [79.3K]

Answer:

4:5

Step-by-step explanation:

You can divide two to each number.

8 divided by 2 equals 4.

10 divided by 2 equals 5.

6 0
3 years ago
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In a certain game, a player can solve easy or hard puzzles. A player earns 30 points for solving an easy puzzle and 60 points fo
Aleksandr-060686 [28]

Answer:  Second option.

Step-by-step explanation:

Let be "e" the number of easy puzzles Tina solved and "h"  the number of hard puzzles Tina solved.

Set up a system of equations:

\left \{ {{e+h=50} \atop {30e+60h=1,950 }} \right.

You can use the Eliminationn Method to solve this system of equations:

  • Multiply the first equation by -30.
  • Add the equations.
  • Solve for "h".

Therefore, through this proccedure, you get:

\left \{ {-30e-30h=-1,500} \atop {30e+60h=1,950 }} \right.\\.........................\\30h=450\\\\h=\frac{450}{30} \\\\h=15

6 0
3 years ago
What are the possible lengths for x, the third side of a triangle, if two sides are 21 and 10
SashulF [63]
To solve we need to use Pythagoras theorem ( a^{2} +  b^{2} =  c^{2} )

There are 2 possible lengths for x: hypotenuse or one of the 2 shorter sides.

Hypotenuse:
10^{2} + 21^2 = x^{2}
100+441= x^{2}
\sqrt{541} =  \sqrt{ x^{2} }
23.3≈x

Shorter leg:
10^2 + x^2=21^2
x^2= 21^2-10^2
x^{2}= 441-100 
\sqrt{ x^{2} } = \sqrt{341}
x≈18.47
8 0
3 years ago
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