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CaHeK987 [17]
3 years ago
15

The fraction 64/72 is a

Mathematics
2 answers:
emmasim [6.3K]3 years ago
5 0
Simplify: 64/72 = 8/9
Hope this helps, If it is pls Brainliest !!
lubasha [3.4K]3 years ago
5 0

Answer:

proper fraction

Step-by-step explanation:

This is a proper fraction, which has a numerator smaller than the denominator

a mixed number has a whole number in front  such as 1  3/5

An improper fraction has a numeration greater than a denominator such as 7/6

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Answer:

thou answer is option C

8 0
4 years ago
Is my answer correct?<br> Will give brainliest!!
Helen [10]
Yes your answer is correct

8 0
3 years ago
How derivative of this absolute value function is like this!
Daniel [21]

Recall the definition of absolute value.

|x| = \begin{cases} x & \text{if } x \ge 0 \\ -x & \text{if } x < 0 \end{cases}

When x,

|x| = x \implies \dfrac{d|x|}{dx} = 1

When x,

|x| = -x \implies \dfrac{d|x|}{dx} = -1

The derivative does not exist at x=0, since the one-sided limits

\displaystyle \lim_{x\to0^-} f'(x) = -1

and

\displaystyle \lim_{x\to0^+} f'(x) = +1

do not match.

So the derivative of |x| is

\dfrac{d|x|}{dx} = \begin{cases} 1 & \text{if } x > 0 \\ -1 & \text{if } x < 0 \\ \text{undefined} & \text{if } x = 0\end{cases}

Now we can write this as

\dfrac{d|x|}{dx} = \dfrac x{|x|} = \dfrac{|x|}x

since

x > 0 \implies |x| = x \implies \dfrac{|x|}x = \dfrac xx = 1

and

x < 0 \implies |x| = -x \implies \dfrac{|x|}x = -\dfrac xx = -1

6 0
1 year ago
I have been having a lot of trouble with this assignment and I don't really understand some of the graph so if anyone can a litt
Zanzabum

Answer:

1. The graph represents the inequality y > 2x + 1

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4 0
3 years ago
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