Question

Precal. Find the sum. Show every step you took to get to your answer. I will give brainliest if you are correct and show all work. ​

Answer 1

Answer:

I think your forgot to add some parts of this question, because you can't do anything with this except simplify it down a little maybe. But, I will provide the simplified version of this.

$\frac{x-4}{x^2-2x}+\frac{4}{x^2-4}$

= $\frac{x-4}{x\left(x-2\right)}+\frac{4}{x^2-4}$

= $\frac{x-4}{x\left(x-2\right)}+\frac{4}{\left(x+2\right)\left(x-2\right)}$

= $\frac{\left(x-4\right)\left(x+2\right)}{x\left(x-2\right)\left(x+2\right)}+\frac{4x}{\left(x+2\right)\left(x-2\right)x}$

= $\frac{\left(x-4\right)\left(x+2\right)+4x}{x\left(x-2\right)\left(x+2\right)}$

= $\frac{x+4}{x\left(x+2\right)}$

Step-by-step explanation:

Hope this helped!