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ElenaW [278]
3 years ago
11

CosA_1+sin1 + 1+sinA_cosA=2secA​

Mathematics
1 answer:
vivado [14]3 years ago
5 0

Step-by-step explanation:

all steps are done in the picture

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The length of a rectangular garden ABCD is 9 feet more than its width. It is surrounded by a brick walkway 4 feet wide as shown
Anna71 [15]

Answer:

  16.5 ft by 25.5 ft

Step-by-step explanation:

Let w represent the width of the garden in feet. Then w+9 is the garden's length, and w(w+9) represents its area.

The surrounding walkway adds 8 feet to each dimension, so the total area of the garden with the walkway is ...

  (w+8)(w+9+8) = w^2 +25w +136

If we subtract the area of the garden itself, then the remaining area is that of the walkway:

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  16w = 264 . . . . . . . . subtract 136

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  w+9 = 25.5 . . . . . . . . . . .length of the garden in feet

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