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almond37 [142]
2 years ago
14

Select the correct answer. Consider this absolute value function. f(x)= |x-5| How can function f be written as a piecewise funct

ion?
(multiple choice)

Mathematics
2 answers:
faltersainse [42]2 years ago
6 0
Option (c) is correct according to me I think it’s helpful
Ksju [112]2 years ago
6 0

Answer:

Option A.

Step-by-step explanation:

An absolute value function can be written in two ways, as the absolute value sign does not allow negative values.

|x-5|=x-5

or

|x-5|=-(x-5)=-x+5

The only options with these equations are A. and D.

D. can be eliminated as the inequalities given for the piecewise function do not match f(x)

To see it visually, you can try graphing it on a calculator or internet graphing service.

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B maybe or A
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CAN ANYONE HELP ME WITH THIS ​
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The angle to the right of y is given as 48.

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the employees of a company were surveyed on questions regarding their educational background ( college degree) and marital statu
Llana [10]

Number employees N = 600

Then

Probability of Single + College degree = ?

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1 year ago
Math Questions :3 thank uu <3
coldgirl [10]
14.       1.5, 10    <- Answer
15.       5,1          <- Answer

Proof 14 

Solve the following system:
{2 x - y = -7 | (equation 1)
4 x - y = -4 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -4 | (equation 1)
2 x - y = -7 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x - y = -4 | (equation 1)
0 x - y/2 = -5 | (equation 2)
Multiply equation 2 by -2:
{4 x - y = -4 | (equation 1)
0 x+y = 10 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = 6 | (equation 1)
0 x+y = 10 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3/2 | (equation 1)
0 x+y = 10 | (equation 2)
Collect results:
Answer: {x = 1.5               
                y = 10

Proof 15. 

Solve the following system:
{5 x + 7 y = 32 | (equation 1)
8 x + 6 y = 46 | (equation 2)
Swap equation 1 with equation 2:
{8 x + 6 y = 46 | (equation 1)
5 x + 7 y = 32 | (equation 2)
Subtract 5/8 × (equation 1) from equation 2:{8 x + 6 y = 46 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 23 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Multiply equation 2 by 4/13:
{4 x + 3 y = 23 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 20 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 5 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer:  {x = 5                           y = 1
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2 years ago
Julie is graduating from college. She has studied biology, chemistry, and computing and hopes to work as a forensic scientist ap
iren2701 [21]

Answer:

A and B

Step-by-step explanation:

4 0
2 years ago
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