Answer:
6 - 5d is an expression equivalent to -5d + 6 using the commutative Property of Addition.
Step-by-step explanation:
Commutative Property of Addition
We know that we can add two numbers in any order.
For example,
Let 'a' and 'b' be two numbers.
We can add 'a' and 'b' numbers in any order, such as
a + b = b + a
Thus,
a + b = b + a is represented using the commutative Property of Addition.
In our case,
-5d + 6 can be written or represented using the commutative Property of Addition, such as
-5d + 6 = 6 - 5d
It is clear that -5d + 6 can be written in any order such as 6 - 5d.
In other words, 6 - 5d is an expression equivalent to -5d + 6 using the commutative Property of Addition.
Therefore, 6 - 5d is an expression equivalent to -5d + 6 using the commutative Property of Addition.
Answer:30
Step-by-step explanation:
45-12=33 nearest tenth is 30
Answer:
The correct response will be "0.01913".
Step-by-step explanation:
According to the question,
p - P(70 years or older)
= 0.18
n = 4
X = no. of individuals who are older than 70 years
Now,
∴ 
∴ 


Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.