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deff fn [24]
3 years ago
9

Slide separated her pictures into 3 piles.Each pile contained 9 pictures.How many pictures did she have in all? Write and solve

an equation to represent the problem.State the answer to the problem.
Mathematics
2 answers:
Artist 52 [7]3 years ago
7 0
Pile = p.

pictures = i.

9i times 3p = total amount of pics. Hope it helps!
swat323 years ago
4 0
Ans.=27
Because if you have 9 pictures in 3 piles you multiply 9 and 3 and you get 27.
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Brainliest for the first correct answer! Which scenario is modeled in the diagram below? (look at attached image)
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Answer:

D) Kaia saved $165.45 on a new guitar because it was 75 percent off. The price of the guitar before the discount was $220.60.

Step-by-step explanation:

Given in the attached diagram shows a model of a discount given on a purchase of guitar showing 75% of the price of guitar ($55.15 + $55.15 + $55.15) that was given.

It also tells that the price pays is 25% of the price of the guitar before the discount. I.e. 25% of %220.60 = 0.25 × 220.60 = $55.15.

From the diagram given, we can infer that Kaia bought the guitar at $55.15 while saving $165.45. That is 25% of the original price. And the amount saved, $165.45, is %75 of the original price ($55.15+$55.15+$55.15).

The answer is D.

7 0
3 years ago
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Answer:

when

Step-by-step explanation:

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Define like terms. Please and thank you.
Step2247 [10]
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Jenny is cooking a chicken for dinner. A chicken needs to be cooked for 40 mins per kilogram, plus an extra 20 mins. How long wi
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7 0
3 years ago
Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.
VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let \mu = <u><em>mean commute time in the U.S..</em></u>

So, Null Hypothesis, H_0 : \mu \geq 30 minutes      {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, H_A : \mu < 30 minutes     {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                           T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean commute time = 27.6 minutes

            s = sample standard deviation = 19.6 minutes

            n = sample of people from the 2000 U.S. Census = 500

So, <u><em>the test statistics</em></u>  =  \frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }  ~ t_4_9_9

                                       =  -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis.</u>

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0
4 years ago
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