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Andrej [43]
3 years ago
14

Rationalize the denominator 2√7+√3/3√7-√3​

Mathematics
2 answers:
kobusy [5.1K]3 years ago
8 0

Answer:

  • (2√7+√3)/(3√7-√3)​ =
  • (2√7+√3)(3√7+√3)​/(3√7-√3)​(3√7+√3)​ =
  • (2*3*√7² + 2√21 + 3√21 + √3²)/(9√7² - √3²) =
  • (42 + 3 + 5√21)/(63 - 3) =
  • (45 + 5√21)/60 =
  • (9 + √21)/12
Dahasolnce [82]3 years ago
5 0

Answer:

\frac{2 \sqrt{7}  + \sqrt{3}}{3 \sqrt{7} -  \sqrt{3}  }  =  \frac{2 \sqrt{7}  + \sqrt{3}}{3 \sqrt{7}  -  \sqrt{3} } . \frac{3 \sqrt{7} +  \sqrt{3}  }{3 \sqrt{7} +  \sqrt{3}  }  \\  \\  =  \frac{(2 \sqrt{7} + 3)(3 \sqrt{7}  +  \sqrt{3})  }{(3 \sqrt{7}  - 3)(3 \sqrt{7} +  \sqrt{3} ) }  \\  \\  =  \frac{(42 + 2 \sqrt{21} + 9 \sqrt{21}   + 3 \sqrt{21} )}{63 - 3}  \\  \\  =  \frac{42 +  2\sqrt{21}  + 9 \sqrt{21} + 3 \sqrt{21}  }{60}

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