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Flura [38]
3 years ago
9

Juanita bought 6 lemons. she used 2/3 of them to make lemonade. how many lemons did she used?

Mathematics
1 answer:
ivanzaharov [21]3 years ago
4 0
6 times 2/3 equal to 4
Juanita ues 4 lemons to make lemonade
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The median is 28; 16,24,x,48
Nookie1986 [14]
x = 32 

To find the media, you take the middle number. If there is no discrete middle number, take the sum of the two closest to the middle and divide by 2. 

(24 + x)/2 = 28

Multiply by 2 on both sides to get:

24 + x = 56

Subtract 24 from both sides to isolate the variable:

x = 56 - 24
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Two pizza delivery drivers compared the mean numbers of deliveries they completed in one day.
marishachu [46]

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B

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Find the interest rate needed for the sinking fund to reach the required amount. Assume that the compounding period is the same
Maslowich

Answer:

so rate is 4.72 %

Step-by-step explanation:

Given data

time (t) = 5 year  = 5×4 = 20 quarterly

amount = $27456

principal = $1225

to find out

interest rate (r)

solution

we use here amount formula that is

amount = principal ((1+r)^{t} -1 ) / r      .....................1

put all value principal , amount and time in equation 1 and we get rate

rate is r/4 because it is quarterly payment

amount = principal ((1+r/4)^{t} -1 ) / r/4

27456 = 1225 ((1+r/4)^{20} -1 ) / r/4

((1+r/4)^{20} -1 ) / r/4  = 27456/ 1225

((1+r)^{20} -1 ) / r  = 27456/ (1225 × 4)

((1+r)^{20} -1 ) = r 27456/ (1225 × 4)

now by the tvm solver and amount  $27456

graph value

we get r = 0.0472

so rate is 4.72 %

5 0
3 years ago
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So no one has the answer?
alexandr402 [8]

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3 years ago
fabiana decides to save the money she is earning from her after school job for college. she makes an initial contribution of 300
Oxana [17]

Answer:

A. Total Money Contributed after n months = \$ 3000 + \$ (500\times n)

B. Total Money Contributed after 24 months = \$ \ 15000

Step-by-step explanation:

Given:

Initial contribution = \$\ 3000

each month contribution =\$\ 500

After 1 month contributed = \$\ 3000 + \$\ 500 \times 1= \$ \ 3500

Solving for Part A

let n be the number of months

∴ Total Contribution after n months = Initial contribution + (each month contribution \times Number of months = \$\ 3000 + \$\ 500 \times n

Solving for Part A

Now n= 24 months

∴ Total Contribution after 24 months = \$\ 3000 + \$\ 500 \times 24 = \$\ 3000 + \$\ 12000= \$\ 15000

3 0
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