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algol13
3 years ago
11

Help help help help me pls !,!,!,

Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer:

96

Step-by-step explanation:

First, you find the area of RPQ using 1/2×base×height. That is, 1/2×6×8. And the answer is 24. Then you multiply 24 by 4 to get the area of all the sides excluding the base to get 96.

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Solve the following equation for x.
Drupady [299]

Answer:

6 {x}^{2}  + 54x + 120 = 0 \\ factors :  4 \: and \:  5 \\ =  (6x  + 24)(x + 5) \\   =  > x =  -4 \: and \:  - 5

5 0
2 years ago
Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and
zloy xaker [14]

Answer:

(0,0)   (4000,0) and (500,79)

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW

\frac{dW}{dt} = -0.02W + 0.00004RW

To solve this, we first equate \frac{dR}{dt} and \frac{dW}{dt} to 0.

So, we have:

0.09R(1 - 0.00025R) - 0.001RW = 0

-0.02W + 0.00004RW = 0

Factor out R in 0.09R(1 - 0.00025R) - 0.001RW = 0

R(0.09(1 - 0.00025R) - 0.001W) = 0

Split

R = 0   or 0.09(1 - 0.00025R) - 0.001W = 0

R = 0   or  0.09 - 2.25 * 10^{-5}R - 0.001W = 0

Factor out W in -0.02W + 0.00004RW = 0

W(-0.02 + 0.00004R) = 0

Split

W = 0 or -0.02 + 0.00004R = 0

Solve for R

-0.02 + 0.00004R = 0

0.00004R = 0.02

Make R the subject

R = \frac{0.02}{0.00004}

R = 500

When R = 500, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0

0.09 -0.01125 - 0.001W = 0

0.07875 - 0.001W = 0

Collect like terms

- 0.001W = -0.07875

Solve for W

W = \frac{-0.07875}{ - 0.001}

W = 78.75

W \approx 79

(R,W) \to (500,79)

When W = 0, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0

0.09 - 2.25 * 10^{-5}R = 0

Collect like terms

- 2.25 * 10^{-5}R = -0.09

Solve for R

R = \frac{-0.09}{- 2.25 * 10^{-5}}

R = 4000

So, we have:

(R,W) \to (4000,0)

When R =0, we have:

-0.02W + 0.00004RW = 0

-0.02W + 0.00004W*0 = 0

-0.02W + 0 = 0

-0.02W = 0

W=0

So, we have:

(R,W) \to (0,0)

Hence, the points of equilibrium are:

(0,0)   (4000,0) and (500,79)

4 0
3 years ago
The tree diagram below illustrates the possible outcomes of three tosses of a balanced coin. What is the probability that “heads
antiseptic1488 [7]
I’m pretty sure its B.1/4
5 0
2 years ago
A random sample of 70 printers discovered that 25 of them were being used in small businesses. find the 95% limit for the popula
kvasek [131]

Answer:

The sample proportion of printers used in small business is:

\hat{p}=\frac{25}{70}=0.3571

The 95% confidence interval for the population proportion of printers that are used in small businesses is:

\hat{p} \pm z_{\frac{0.05}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n} }

Where:

z_{\frac{0.05}{2}}=1.96 is the critical value at 0.05 significance level

\therefore 0.3571 \pm 1.96 \sqrt{\frac{0.3571(1-0.3571)}{70} }

         0.3571 \pm 0.1122

         \left ( 0.3571 - 0.1122, 0.3571 + 0.1122 \right)

         \left(0.245,0.469 \right)

Therefore, the 95% confidence interval for the population proportion of printers that are used in small businesses is (0.245 , 0.469)



7 0
3 years ago
Given f(x)=8x^5, find f^-1(x) <br> Then state whether f^1(x) is a function.
irina1246 [14]

Answer:

f^-1(x) = (x/8)^(1/5) is a function

Step-by-step explanation:

The inverse of a function is the function reflected across the line y=x. This results in the coordinate points (x,y) of the function becoming (y,x) for the inverse function. Algebraically to find the inverse, switch the x and y locations and solve for y.

y = 8x^5

x = 8y^5

x/8 = y^5

(5)√(x/8) = y

This is a fifth root of (x/7) also written in exponents as y = (x/8)^(1/5).

This is a function. While it appears not to be a function because the middle portion over the origin appears vertical, it is a function because the middle portion over the origin is changing and graphing software shows it has no input with more than one output. Without graphing software you would rule it is not a function.

6 0
3 years ago
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