Answer:
Use the chart below to help you. Follow the arrows
Explanation:
For instance, number 8 is where liquid is going to solid. The chart tells you that it's freezing.
C.354
1L/1000cm^3
0.354L/ycm^3 *1L/1000cm^3
Cross multiply 0.354 by 1000and then divide by one to get 354.
I assume you’re looking for a balanced equation.
SiCl4 + 2H2O = SiO2 + 4HCl
ANSWER:
B. Electrons have transferred from one atom to another.
EXPLANATION:
An oxidation-reduction (redox) reaction is a reaction which involves the change in oxidation number of the atoms involved. Since the oxidation number changes, this means that one atom has to lose electrons and another has to accept electrons. The reactant that loses electrons is called REDUCING AGENT while the reactant that gains electrons is called OXIDIZING AGENT.
For example, in a reaction between iron and oxygen as follows:
4Fe+ 3O2→2Fe2O3
Iron is reduced from +2 to 0 because it accepts electrons from oxygen while oxygen is oxidized from -2 to 0 because it transfers electrons to iron.
Hence, a redox reaction can be identified by the transfer of electrons from one atom to another.
Learn more: brainly.com/question/13293425
Since, we have the reaction as,
2Li(s) + F2(g) --> 2LiF(s)
we are only concerned with the limiting reactants. We calculate for the amount of product that can be produced with the given amount of reactants.
a. 1 g Li(1 mol / 6.941 g of Li)(2 mol LiF/2 mol Li) = 0.144 mol LiF2
1 g F2(1 mol/38 g)(2 mol LiF2/1 mol F2) = 0.052 mol LiF2
Answer: 1 g of F2
b. 10.5 g Li(1 mol/6.941 g of Li)(2 mol LiF/2 mol Li) = 1.512 mol LiF2
37.2 g F2(1 mol/38 g)(2 mol LiF2/1 mol F2) = 1.958 mol LiF2
Answer: 10.5 g of Li
c. (2.85 x 10^3 g Li)(1 mol/6.941 g of Li)(2 mol LiF/2 mol Li) = 410.60 mol LiF2
(6.79 x 10^3 g F2)(1 mol/38 g)(2 mol LiF2/1 mol F2) = 357.368 mol of LiF2
Answer: 6.79 x 10^3 g F2