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butalik [34]
3 years ago
8

How do you determine which variable is independent and which one is independent?

Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0
Answer: An independent variable is exactly what it sounds like. It is a variable that stands alone and isn't changed by the other variables you are trying to measure. For example, someone's age might be an independent variable.
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Solve for x: -6(x + 4) + 9 > -5(x + 6)
devlian [24]

Answer:

x < 15

Step-by-step explanation:

Let's first expand the parentheses on both sides. Remember that when expanding parentheses, the result will be the sum of the products of the "outside number" with each of the "inside number".

On the left, the parenthetical expression is: -6(x + 4). Here, the outside term is -6 and the inside terms are x and 4. So:

-6(x + 4) = -6 * x + (-6) * 4 = -6x - 24

On the right, the parenthetical expression is: -5(x + 6). Here, the outside term is -5 and the inside terms are x and 6. So:

-5(x + 6) = -5 * x + (-5) * 6 = -5x - 30

Now put these back in:

-6(x + 4) + 9 > -5(x + 6)

-6x - 24 + 9 > -5x - 30

-6x - 15 > -5x - 30

x < 15

Thus the answer is x < 15.

Hope this helps!

3 0
3 years ago
Solve by substitution y=x+4, y=2x+5
Amiraneli [1.4K]
X+4=2x+5
-1=x
hope this helps
4 0
2 years ago
What is X for? x+20=35-4x
Helen [10]
X+4x=35-20. 5x=35-20. 5x=15. X=3
4 0
3 years ago
Read 2 more answers
I’m about to cry from frustration. Help please before I die
kvv77 [185]

Answer:

\frac{1}{3}x+16=37

63 Jelly Beans

Step-by-step explanation:

The unknown is the number of jelly beans originally in the bag or x

First he had x jelly beans

The he ate one-third of them

\frac{1}{3}x

He then ate 16 more jelly beans

\frac{1}{3}x+16

This was equal to 37 jelly beans

\frac{1}{3}x+16=37

This is the equation

Now solve for x

Subtract 16 from both sides

\frac{1}{3}x=21

Multiply both sides by 3

x=63

63 Jelly Beans

7 0
3 years ago
Read 2 more answers
Simplify completely 2x-24 over 8
77julia77 [94]

Answer:

x-12/4


Step-by-step explanation:

hope its correct :-)

8 0
3 years ago
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