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Naddik [55]
3 years ago
6

What is the average rate of change between x=1 and x=5 for y=2x+5

Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0

Answer:

the average rate of change is 2 with an intercept of 5

Step-by-step explanation:

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Please help me with this!<br><br><br> show that {1,2} ⊆ {x|x^4 - x^3 - x^2 - 5x + 6 = 0}
Llana [10]

The set \{x\mid x^4-x^3-x^2-6x+6=0\} is the set of all values of x that are solutions to the given equation. So all you need to do is check whether x=1 and x=2 satisfy the equation.

x=1\implies 1^4-1^3-1^2-5+6=0

x=2\implies2^4-2^3-2^2-10+6=0

The equation holds, so both 1 and 2 are solutions, and hence \{1,2\} is a subset of the solutions.

6 0
3 years ago
Use completing the square to solve for x in the equation (x+7)(x-9)=25
lara31 [8.8K]

Answer: x=1+89

answer number 3

Step-by-step explanation:

8 0
2 years ago
The larger of two numbers is 10 less than twice the smaller number. If the sum of the two
natka813 [3]

Answer:

Let the larger number = y and the smaller number = x.

The largest number is 10 less than twice the smaller number. Remember that less than means subtract the 10 from the other amount while twice means multiply by two. Therefore,

y = 2x - 10

The sum of the two numbers is 38. Remember sum means add the two numbers to get their result. Therefore,

x + y = 38

Since y = 2x - 10, we rewrite the lower equation as:

x + (2x - 10) = 38

Solving:

3x - 10 = 38

3x = 48

x = 16

The lesser number is 16 and the greater number is 2(16) - 10 or 22.

7 0
3 years ago
Note: When solving for k, round to four decimals places **
____ [38]
First we find k by using the two values given:
P=Ae^(kt), 8 years between-->t=8
199 = 195•e^(8k)
Log 199 = Log [195•e^(8k)]
Log 199 = Log 195 + 8k
8k = Log 199 - Log 195
k = 0.00882/8 = .0011
Next, we plug the new data in using this k:
14 years between 2002-2016-->t=14
P = Ae^my
P = 199mi.•e^(14•.0011)
P = 199mi.•e^(.0154)
P = 199mi. • 1.0155 = 202,088,000
5 0
3 years ago
At the moment a hot iron rod is plunged into freezing water, the difference between the rod's and the
jonny [76]

Answer:

<h2>The function is</h2><h2>D(t) = 100 \times( \frac{40}{100} )^{t}</h2>

Step-by-step explanation:

At t = 0 the difference is 100 degree celsius.

After one second the temperature difference will be 100 - \frac{100\times60}{100} = 100(1 - \frac{60}{100} )

After two second, the difference will be 100(1 - \frac{60}{100} )(1 - \frac{60}{100} ) = 100(1 - \frac{60}{100} )^{2}

Hence, it can be written that,

D(t) = 100 \times(1 - \frac{60}{100} )^{t} = 100 \times( \frac{40}{100} )^{t}

5 0
4 years ago
Read 2 more answers
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