I believe it's B. I hope this helps
1=104 2=76 3=104 4=76 5=104 6=76 7=104 8=76
Answer:
X = 96
Step-by-step explanation:
This one is pretty simple
So we're dealing with angles here.
So what we want to do is add the two angles and it =180
Here's the equation so it makes more sense:
so we'd place in those numbers
add the two angles together
than we'd subtract from 180 getting the value of X
The first step to solve this problem is to find 10% of 3,500. To do this you would set up the equation x/3,500=10/100. You then multiply 3,500 by 10, getting 35,000, then divide that by 100. The 10% would then be 350. Finally, you would subtract 350 from 3,500, getting 3,150 as your final answer.
(i) Velocity is the rate of change of position, so if
<em>r</em><em>(t)</em> = <em>b</em> cos(<em>ω t </em>) <em>i</em> + <em>b</em> sin(<em>ω t </em>) <em>j</em> + <em>v</em> <em>t</em> <em>k</em>
then
<em>v</em><em>(t)</em> = d<em>r</em>/d<em>t</em>
<em>v</em><em>(t)</em> = -<em>b</em> <em>ω </em>sin(<em>ω t</em> ) <em>i</em> + <em>b</em> <em>ω</em> cos(<em>ω</em> <em>t</em> ) <em>j</em> + <em>v</em> <em>k</em>
The speed of the particle is the magnitude of the velocity, given by
|| <em>v</em><em>(t)</em> || = √[(-<em>b</em> <em>ω </em>sin(<em>ω t</em> ))² + (<em>b</em> <em>ω</em> cos(<em>ω</em> <em>t</em> ))² + <em>v</em> ²]
… = √[<em>b </em>²<em>ω </em>² + <em>v</em> ²]
(ii) The path is a helix. Suppose you zero out the <em>k</em> component. Then the path is a circle of radius <em>b</em>, and the value of <em>ω</em> determines how quickly a particle on the path traverses the circle. Now if you reintroduce the <em>k</em> component, the value of <em>v</em> will determine how far from the plane <em>z</em> = 0 the particle moves in a helical path as <em>t</em> varies.
(iii) Acceleration is the rate of change of velocity, so
<em>a</em><em>(t)</em> = d<em>v</em>/d<em>t</em>
<em>a</em><em>(t)</em> = -<em>b</em> <em>ω </em>²<em> </em>cos(<em>ω t</em> ) <em>i</em> - <em>b</em> <em>ω</em> ² sin(<em>ω</em> <em>t</em> ) <em>j</em>
