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2 years ago

What is 4,328.12 in expanded form?

Mathematics

1 answer:

shepuryov [24]2 years ago

4 0

Hope this helps

Answer = 4,328.12
4,000
300
20
8
0.1
0.02

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How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy

lisov135 [29]

Answer:

$300\; \rm lb$ .

Step-by-step explanation:

Let $x$ represent the mass (in pounds) of that $15\%$ copper alloy required, such that the final mixture would contain $25.5\%$ copper by mass.

Consider: if $x$ pounds of that $15\%$ copper alloy is mixed with $700$ pounds that $30\%$ copper alloy, what would be the mass of copper in the mixture?

Mass of copper in $x$ pounds of that $15\%$ copper alloy: $(0.15\, x)\; \rm lb$ .
Mass of copper in $700$ pounds of that $30\%$ copper alloy: $700 \times 0.30 = 210\; \rm lb$ .

Therefore, the mixture would contain $(210 + 0.15\, x) \; \rm lb$ of copper.

The mass of that mixture would be $(700 + x)\; \rm lb$ . The mass fraction of copper in that mixture would be:

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%$ .

This ratio is supposed to be equal to $25.5\%$ . These two pieces of equations combine to give an equation about $x$ :

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%$ .

$\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255$ .

Simplify and solve for $x$ :

$210 + 0.15\, x= 0.255\, (700 + x)$ .

$(0.255 - 0.15)\, x= 210 - 0.255 \times 700$ .

$\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300$ .

Therefore, $300\; \rm lb$ of that $15\%$ alloy would be required.

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2 years ago

bonufazy [111]

If similarity ratio means the ratio between the lengths of the cubes:

$\frac{ L_1^{3} }{ L_2^{3} } = \frac{V_1}{V_2} \\ \\ ratio = \frac{L_1}{L_2} = \frac{\sqrt[3]{V_1} }{\sqrt[3]{V_2} }$

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2 years ago

three friends are in the same algebra class. Their scores on a recent test are three consecutive odd intergers whose sum is 279.

jasenka [17]

X= 1st integer
x+2= 2nd integer
x+4= 3rd integer

Add the integers together

x + (x + 2) + (x + 4)= 279
combine like terms
3x + 6= 279
subtract 6 from both sides
3x= 273
divide both sides by 3
x= 91 first integer

Substitute x=91 to find 2nd & 3rd integers

2nd Integer
=x+2
=91+2
=93

3rd Integer
=x+4
=91+4
=95

ANSWER: The three test scores are 91, 93 and 95.

Hope this helps! :)

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2 years ago

Complete the square to write the equation, 4x2 + 24x – y + 43 = 0, in standard form.

Tamiku [17]

Answer:

y=4

x=3

Step-by-step explanation:

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2 years ago

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