You use the discriminant (b²-sqr(4ac))/2a and if sqr(4ac) inferior to 0 then use i = sqr(-1)
To evaluate the series we proceed as follows:
2. -5,-15,-25,-35,-45
The common difference is (-15--5)=-10
thus the series is an arithmetic sequence hence the explicit formula will be:
an=a+(n-1)d
thus the formula for the series is:
an=-5+(n-1)(-10)
an=-10n+5
4. 0.5, 0.25,0,...,-0.75
The common difference =0.25-0.5=-0.25
The sequence is an arithmetic sequence:
the explicit formula will be:
an=0.5-0.25(n-1)
an=-0.25n+0.75
thus
n=4
a4=-0.25*4+0.75=-0.25
when n=5
a5=-0.25*5+0.75=-0.5
when n=6
a6=-0.25*6+0.75=-0.75
the missing values are -0.25 and -0.5
6] 4.5,5.6,6.7, ....,11.1
common difference=5.6-4.5=1.1
the sequence is an arithmetic sequence
The explicit formula is:
an=4.5+1.1(n-1)
an=1.1n+3.4
when n=4
an=1.1*4+3.4
a4=7.8
when n=5
a5=1.1*5+3.4
a5=8.9
a6=1.1*6+3.4
a6=10
the missing values are: 7.8, 8.9, 10
Answer:
The volume of the tumor experimented a decrease of 54.34 percent.
Step-by-step explanation:
Let suppose that tumor has an spherical geometry, whose volume (
) is calculated by:
Where 
is the radius of the tumor.
The percentage decrease in the volume of the tumor (
) is expressed by:
Where:
- Absolute decrease in the volume of the tumor.
- Initial volume of the tumor.
The absolute decrease in the volume of the tumor is:
The percentage decrease is finally simplified:
![\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%](https://tex.z-dn.net/?f=%5C%25V%20%3D%20%5Cleft%5B1-%5Cleft%28%5Cfrac%7BR_%7Bf%7D%7D%7BR_%7Bo%7D%7D%5Cright%29%5E%7B3%7D%20%5Cright%5D%5Ctimes%20100%5C%2C%5C%25)
Given that 
and 
, the percentage decrease in the volume of tumor is:
![\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%](https://tex.z-dn.net/?f=%5C%25V%20%3D%20%5Cleft%5B1-%5Cleft%28%5Cfrac%7B0.77%5Ccdot%20R%7D%7BR%7D%5Cright%29%5E%7B3%7D%20%5Cright%5D%5Ctimes%20100%5C%2C%5C%25)
The volume of the tumor experimented a decrease of 54.34 percent.
The length of the line segment is 24 cm.
