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4 years ago

Help with this one please

Mathematics

1 answer:

den301095 [7]4 years ago

3 0

point R ((:

reason being (-5,-6) over the y axis is (5, -6)

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Bo, Ryan and Zach walked 1/4 miles from school to Bo’s house. They walked 4/6 miles from Bo's House to the park what is the tota

BigorU [14]

Answer: They walked 11/12 miles

Step-by-step explanation:

1/4 + 4/6

3/12 + 8/12

11/12

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3 years ago

What is equal to 13 centimeters.

atroni [7]

Answer:

5.11811 inches

Step-by-step explanation:

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2 years ago

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Complete the sentence below.<br><br> The expression 52x – 169 is equivalent to 13(<br> )

gladu [14]

Answer:

13(4x-13)

if you distribute it then you come back with 52x-169.

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3 years ago

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It took 3/4h to complete 1game of cards.How many games can be completed 2 1/4h?

Crank

I would prefer to solve this in a decimal form
I will show this to u in 2 ways
1:.75::X:2.25
(1*2.25)/.75x
2.25/.75x
X=3

2.25/.75=3
when we divide the number of hours played by hors for one game we get the number of games that could be played

7 0

4 years ago

I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu

ra1l [238]

The imaginary unit $i$ belongs to the set of complex numbers, denoted by $\mathbb C$ . These numbers take the form $a+bi$ , where $a,b$ are any real numbers.

The set of real numbers, $\mathbb R$ , is a subset of $\mathbb C$ , where each number in $\mathbb R$ can be obtained by taking $b=0$ and letting $a$ be any real number.

But any number in $\mathbb C$ with non-zero imaginary part is not a real number. This includes $i$ .

"is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because $2=2+0i$ .

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising $i$ to the $i$ -th power. Since $i=e^{i\pi/2}$ , we have

$i^i=\left(e^{i\pi/2}\right)^i=e^{i^2\pi/2}=e^{-\pi/2}\approx0.2079$

3 0

3 years ago