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Elza [17]
3 years ago
8

Seven less than four times a number is 29 equation pleasee

Mathematics
2 answers:
Daniel [21]3 years ago
6 0

4n - 7 = 29

That's the equation  :)

You can use any variable; doesn't have to be n.

If you want to solve for the variable, then it would be 5.5

Alla [95]3 years ago
6 0

Answer:

7-4*x = 29

Step-by-step explanation:

All you have to do is take 7 subtract it by 4 then times that by x (random number) and the =29 and just put that into an equation. Please tell me if that doesn't make sense lol.

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Jon has to pay $7.00 admission for the skating rink in $1.50 per hour to rent rollerblades. How many hours can he skate for $19?
eduard

Answer: 8 hours

Step-by-step explanation:

<u>Given information</u>

Admission fee = $7.00

Hour rent fee = $1.50

Number of hours = h

Total fee = $19

<u>Set equation according to the given information</u>

Total fee = admission fee + (hours) × (hour rend fee)

<u>Substitute values into the equation</u>

19 = 7 + 1.5h

<u>Subtract 7 on both sides</u>

19 - 7 = 7 + 1.5h - 7

12 = 1.5h

<u>Divide 1.5 on both sides</u>

12 / 1.5 = 1.5h / 1.5

\boxed{h=8}

Hope this helps!! :)

Please let me know if you have any questions

5 0
3 years ago
Calvin paints pictures and sells them at art shows. He charges $ 56.25 for a large painting. He charges $25.80 for a small paint
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Read 2 more answers
Segment AB has length a and is divided by points P and Q into AP , PQ , and QB , such that AP = 2PQ = 2QB. A) Find the distance
Deffense [45]

Answer:

A) \frac{7}{8}a

B) \frac{5}{8}a

Step-by-step explanation:

AB has length a and is divided by points P and Q into AP , PQ , and QB , such that AP = 2PQ = 2QB

A) Therefore, AP = 2QB

QB = AP/2

The midpoint of QB = QB/2 = (AP/2)/2 = AP/4

AP = 2PQ, Therefore PQ = AP/2

Since the length of AB = a

AB = AP + PQ + QB = a

AP + AP/2 + AP/2 = a

AP + AP = a

2AP = a

AP = a/2

The distance between point A and the midpoint of segment QB = AP + PQ + QB/2 = AP + AP/2 + AP/4 = 7/4(AP)

But AP = a/2

Therefore The distance between point A and the midpoint of segment QB =  7/4(a/2)= \frac{7}{8}a

B)

the distance between the midpoints of segments AP and QB = AP/2 + PQ + QB/2 = AP/2 + AP/2 + AP/4 = 5/4(AP)

But AP = a/2

Therefore the distance between the midpoints of segments AP and QB = 5/4(AP) = \frac{5}{4} *\frac{a}{2}=\frac{5}{8}a

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