That would be a variable, x being one of the most commonly used variables to represent unknown numbers.
Answer:

Step-by-step explanation:
625 when divided by 5 gives 125 which is a perfect cube.
=> 
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
![\sf \ \sqrt[3]{125} = 5](https://tex.z-dn.net/?f=%5Csf%20%20%20%20%5C%20%20%5Csqrt%5B3%5D%7B125%7D%20%3D%205)
So, 5 needs to be divided by 625 to make the quotient a perfect cube!
Answer:
17
Step-by-step explanation:
Answer:
length = 2x = 2(9) = 18 yds
Step-by-step explanation:
Let width = x
Let length = 2x
Area = 162 yd2
length × width = Area
2x(x) = 162
2x2 = 162
Divide by 2 on both sides of equation.
x2 = 81
Square-root both sides of equation to undo the exponent.
x = √(81)
x = 9
Substitute this x value into the initial variables.
width = x = 9 yds
length = 2x = 2(9) = 18 yds
Answer:
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Step-by-step explanation:
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