Three consecutive numbers are x, x+1 and x+2.
Four times the first integer is 4x
The sum of the second and third is (x+1)+(x+2)=2x+3.
So, we have

Subtract 2x from both sides:

Divide both sides by 2:

So, you can't have three consecutive integers such that four times the first is 18 more than the sum of the other two: the three numbers would be 10.5, 11.5, 12.5.
In fact, you have

and

Answer:16 is x
Step-by-step explanation:
this is a equilateral triangle witch means the sides are the same. 3x is more than 2x so they put - 8 to get to 2 x and 8 times 2 is 16 and there you go.
Answer:
B) 43in^2
Step-by-step explanation:
I did the work but I'm very bad at explaining it. What I can say is area of 2 little square is 9 so 9x2=18 Then area of big square is 25 so 25+18= 43
Answer:
1) ABCD is a rhombus
2) All sides of a rhombus are equal.
4) SSS
5) CPCTC
Answer:
<em>y=-6</em>
Step-by-step explanation:
<em>Geometric Sequences</em>
Any given sequence is said to be geometric if each term
can be obtained as the previous term
by a constant value called the common ratio.

or equivalently

Looking closely at the sequence 2, y, 18,-54, 162 we can try to find out if it's a geometric sequence or not. We compute the possible common ratios
and we see they both result -3. If we use r=-3 and try to find the second term (y), then
y=2*(-3)=-6
Now we compute the third term: (-6)(-3)=18
Since we got the third term as given in the original sequence.
So y=-6