Question

Factorize: 7xyz + 21x^2 y​

Answer 1

Answer:

$7xyz + 21 {x}^{2} y$

factorise out 7, x and y:

$= 7xy(z + 3x)$

Answer 2

Answer:

$\huge\boxed{\sf 7xy (z + 3x)}$

Step-by-step explanation:

$\sf 7xyz +21x^2y\\\\H.C.F. = 7xy\\\\Hence, \ Take \ 7xy \ as \ common\\\\= 7xy (z + 3x)\\\\\rule[225]{225}{2}$

Hope this helped!

~AH1807

Peace!