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kati45 [8]
3 years ago
15

What is root3(root3 - 1)

Mathematics
2 answers:
Furkat [3]3 years ago
7 0

\boxed{\blue{ 3-\sqrt{3} } }

Step-by-step explanation:

\bold{\sqrt{3}(\sqrt{3}-1)   }

\bold{\sqrt{3}(\sqrt{3})-\sqrt{3}(1)   }

\bold{(\sqrt{3})^2-\sqrt{3}   }

\bold{ 3-\sqrt{3}  }

Alenkasestr [34]3 years ago
4 0

Answer:

  • 3 - root3 or 3 - √3

Step-by-step explanation:

  • root3(root3 - 1) =
  • √3(√3 - 1) =
  • √3(√3) - √3(1) =
  • √3² - √3 =
  • 3 - √3
  • 3 - root3
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Dmitriy789 [7]
The answer to this question is 5x3-3x2-5x+3
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3 years ago
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The ice cream vendor 's cold box holds 24 ice cream cups. The
jeyben [28]

Answer:

16

Step-by-step explanation:

24/8=3

48/3=16

7 0
3 years ago
Can someone help me with this? I need to find the points of discontinuity/limits for each of these. I think one point is 4, but
Debora [2.8K]
The answers are shown in the attached image

-------------------------------------------------------------------------

Explanation:

Set the denominator x^4-8x^3+16x^2 equal to zero and solve for x

x^4-8x^3+16x^2 = 0
x^2(x^2-8x+16) = 0
x^2(x-4)^2 = 0
x^2 = 0 or (x-4)^2 = 0
x = 0 or x-4 = 0
x = 0 or x = 4

The x values 0 and 4 make the denominator zero

These x values lead to asymptote discontinuities because the numerator 8x-24 = 8(x-3) has no common factors which cancel with the denominator factors.

There are two vertical asymptotes

Let's see what happens when we plug in a value to the left of x = 0, say x = -1, we'd get
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(-1) = (8(-1)-24)/((-1)^4-8(-1)^3+16(-1)^2)
f(-1) = -1.28
So as x gets closer and closer to x = 0 from the left side, the f(x) is heading to negative infinity

Now plug in some value to the right of x = 0. I'm going to pick x = 1
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(1) = (8(1)-24)/((1)^4-8(1)^3+16(1)^2)
f(1) = -1.78 (approximate)
So as x gets closer and closer to x = 0 from the right side, the f(x) is heading to negative infinity

Overall, as x approaches 0 from either the left or right side of x = 0, the y value is heading off to negative infinity

---------------------

Repeat for values to the left and right of x = 4
We can't use x = 1 as it turns out that x = 3 is a root
But we can use something like x = 3.5 to find that...
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(3.5) = (8(3.5)-24)/((3.5)^4-8(3.5)^3+16(3.5)^2)
f(3.5) = 1.31 approx
So as x gets closer to x = 4 from the left, y is getting closer to positive infinity

Plug in x = 5 to find that
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(5) = (8(5)-24)/((5)^4-8(5)^3+16(5)^2)
f(5) = 0.64
which has the same behavior as the left side

So overall, as we approach x = 4, the y value is heading off to positive infinity

Again everything is summarized in the image attachment

Note: you could make a table of more values but they would effectively say what has already been said. It would be redundant busy work. However, its always good practice for function evaluation. 

6 0
3 years ago
Please help! It’s Saturday and I only have this question left on my digital worksheet!
Natalija [7]

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

<h3>\frac{ {6}^{ - 3} }{ {6}^{5} }</h3>

Using the rules of indices

Since the bases are the same and are dividing we subtract the exponents

That's

<h3>\frac{ {a}^{x} }{ {a}^{y} }  =  {a}^{x - y}</h3>

So we have

<h3>\frac{ {6}^{ - 3} }{ {6}^{5} }  =  {6}^{ -  3 - 5}  =  {6}^{ - 8}</h3>

Using the rules of indices

<h3>{x}^{ - y}  =  \frac{1}{ {x}^{y} }</h3>

So we have the final answer as

<h2>\frac{1}{ {6}^{8} }</h2>

Hope this helps you

4 0
3 years ago
Write the expanded form of 5360
Over [174]

Answer:

5000+300+60+0

Step-by-step explanation:

4 0
1 year ago
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