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Leviafan [203]
2 years ago
6

Please help me, i need the answers ASAP! (With proper steps please)

Mathematics
1 answer:
docker41 [41]2 years ago
4 0

a) 35 x 13 + 3.14 x \frac{13}{2}²

= 455 + 3.14 x 42.25

= 455 + 132.665

= 587.665 m²

∴ The area is  587.665 m².

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2) A rectangular pyramid has the base area measuring 30 m by 20 m. Given 1 point
Hitman42 [59]

Answer:

20x30xH=7000

11.6666 , depends on how much you need to round it. if 2 sig figs, round it to 12.

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2 years ago
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Solve the equation 36w = 16w + 24
Umnica [9.8K]
=24/20 thus the answer is 1.2
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3 years ago
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Please help me, you will get 20 points:)
ASHA 777 [7]
Dont listen to the person above, they put the same link everhwher
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Two similar pyramids have lateral areas 8ft^2 and 18 ft^2. the volume of the large pyramid is 108 ft^2. find the volume of the s
ddd [48]
I assume the volume of the larger pyramid is 108 ft^3, not 108 ft^2.

The scale factor of edges of two solids is x.
The scale factor of their areas is x^2.
The scale factor of their volumes is x^3

The areas have a scale factor of 18/8 = 2.25

The length have a scale factor of sqrt(2.25) = 1.5

The volumes have a scale factor of 3.375

108/3.375 = 32

Answer: 32 ft^3
4 0
3 years ago
11 people enter a pie eating contest. how many ways can the prize be awarded to the top 3
True [87]
This is a permutation question because we care about the order.
We can demonstrate this by letting each person be a person in the pie eating contest.

A   B   C   D   E   F   G   H   I   J   K

_   _   _

Now, there are 11 ways for the first prize to be won, since there are no restrictions upheld. Let's say A wins the first prize.

B   C   D   E   F   G   H   I   J   K

A   _   _

Now, assuming prizes aren't shared, there are only ten people left to win the second prize.
Using this logic, then we can say that nine can win the third prize.

Thus, our answer is 11 · 10 · 9 = 990 ways.

However, this method works for this question.
What happens when the number of places we want gets significantly larger?
That's when we introduce the permutation formula.

We know that 11·10·9·8·7·6·5·4·3·2·1 = 11!, but we don't want 8! of them.
This is the formula for permutation.

^{11}P_3 = \frac{11!}{(11 - 3)!} = 990
8 0
3 years ago
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