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Volgvan
3 years ago
13

You are trying to determine if an object is living or nonliving.

Biology
1 answer:
Afina-wow [57]3 years ago
7 0

Answer: a,b,c,d

Explanation:

all four of them are characteristics in all living organisms. All living things will grow and change, it will move otherwise it wouldn’t be able to get the nutrients it may need (or run away from predators), in order for the species to go on, they must reproduce, and they must maintain homeostasis so that they don’t freeze of burn to death. but however, it is not required for the living organism to be made up of only one cell, take humans for example.

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Why is glycolysis described as having an investment phase and a payoff phase?
Reil [10]

Answer:

Stored ATP is used and in the process it forms a net increase in ATP

Explanation:

It needs 2 ATP at the start of glycolysis (investment phase) and produces four ATP molecules, and two molecules of NADH at the end (payoff phase)

3 0
3 years ago
More energy is required to raise the temperature of __________ so it heats and cools very slowly.
swat32

Answer:

The specific heat of a substance is the amount of energy required to raise the temperature of 1 gram of the substance by 1°C. Table below lists the specific ...

Explanation:

4 0
3 years ago
In cucumbers, dull fruit (D) is dominant over glossy (d) fruit, orange friut (R) is dominant over cream fruit (r), and bitter co
stiv31 [10]

Explanation:

  • Dull fruit (D) is dominant over glossy (d) fruit.
  • Orange friut (R) is dominant over cream fruit (r).
  • Bitter cotyledon (B) is dominant over non-bitter cotyledons (b).

The three genes are independent.

<h3>a)</h3>
  • A plant homozygous for dull, orange fruit and bitter cotyledons has the genotype <em>DDRRBB</em><em>.</em>
  • A plant homozygous for glossy, cream fruit and non-bitter cotyledons has the genotype <em>ddrrbb</em>.

100% of the F1 will have dull, orange fruit and bitter cotyledons and will be heterozygous for all genes: <em>DdRrBb</em>.

<u>The F2 will have 8 possible phenotypes:</u>

  • 27 D_R_B dull, orange fruit and bitter cotyledons
  • 9 D_R_bb dull, orange fruit and non-bitter cotyledons
  • 9 D_rrB_ dull, cream fruit and bitter cotyledons
  • 3 D_rrbb dull, cream fruit and non-bitter cotyledons
  • 9 ddR_B_ glossy, orange fruit and bitter cotyledons
  • 3 ddR_bb glossy, orange fruit and non-bitter cotyledons
  • 3 ddrrB_ glossy, cream fruit and bitter cotyledons
  • 1 ddrrbb  glossy, cream fruit and non-bitter cotyledons

<h3>b)</h3>

An F1 plant is crossed with a plant that has glossy, cream fruit and non-bitter cotyledons.

<h3>DdRrBb x ddrrbb </h3>

The F1 individual can produce 8 types of gametes: DRB, DRb, DrB, Drb, dRB, dRb, drB and drb. The cream fruit and non-bitter cotyledons individual can only produce drb gametes. This cross also produces a progeny with the following genotypes and phenotypic proportions:

  • 8 DdRrBb dull, orange fruit and bitter cotyledons
  • 8 DdRrbb dull, orange fruit and non-bitter cotyledons
  • 8 DdrrBb dull, cream fruit and bitter cotyledons
  • 8 Ddrrbb dull, cream fruit and non-bitter cotyledons
  • 8 ddRrBb glossy, orange fruit and bitter cotyledons
  • 8 ddRrbb glossy, orange fruit and non-bitter cotyledons
  • 8 ddrrBb glossy, cream fruit and bitter cotyledons
  • 8 ddrrbb  glossy, cream fruit and non-bitter cotyledons

4 0
3 years ago
The cell division process that produces daughter cells with half the chromosome of the parent cell is _________.
STatiana [176]

Answer: Mitosis (A)

Explanation:

5 0
3 years ago
If a person weighs 818 N on earth and 5320 N on the surface of a nearby planet, what is the acceleratic due to gravity on that p
lord [1]
It would be c.
Gravity force on earth: 9.8N or m/s estimed to 10N
818/10= 81.8 kg on earth
form the equation:
81.8×x=5320
If we solve this equation we will get an answer near 63.7 m/s.
8 0
3 years ago
Read 2 more answers
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