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mariarad [96]
3 years ago
8

A= 12b1+b2h ; solve for b1

Mathematics
1 answer:
HACTEHA [7]3 years ago
5 0

Answer:

b1 = 2A/h – b2

Step-by-step explanation:

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Explain how to solve the equation by reasoning about numbers, operations, and expressions. Do NOT use standard algebraic equatio
Brilliant_brown [7]

Answer:

x=924

Step-by-step explanation:

348 + 926 = x + 350

we have two 2-terms additions in both sides of the equation.

348 and 350 are two <em>similar</em> numbers then x and 926 should be really <em>close</em> numbers.

(due to commutative property of additions 348 + 926 = 350 + x)

<em>since 348 has two units less than 350, then 926 must have two units more than x, and <u>x=924</u></em>

(indirect proportionality)

6 0
4 years ago
Which equation represents a linear function?
devlian [24]

Answer:

y = 9 - x

Step-by-step explanation:

y = 9 - x

3 0
3 years ago
Read 2 more answers
In a random sample of 380 cars driven at low altitudes, 42 of them exceeded a standard of 10 grams of particulate pollution per
alexdok [17]

Answer:

The test statistic for testing if the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard is 3.234.

Step-by-step explanation:

We are given that in a random sample of 380 cars driven at low altitudes, 42 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed.

In an independent random sample of 90 cars driven at high altitudes, 24 of them exceeded the standard.

Let p_1 = <u><em>population proportion of cars driven at high altitudes who exceeded a standard of 10 grams</em></u>.

p_2 = <u><em>population proportion of cars driven at low altitudes who exceeded a standard of 10 grams</em></u>.

So, Null Hypothesis, H_0 : p_1\leq p_2      {means that the proportion of high-altitude vehicles exceeding the standard is smaller than or equal to the proportion of low-altitude vehicles exceeding the standard}

Alternate Hypothesis, H_A : p_1>p_2      {means that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard}

The test statistics that will be used here is <u>Two-sample z-test statistics</u> for proportions;

                             T.S.  =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~  N(0,1)

where, \hat p_1 = sample proportion of cars driven at high altitudes who exceeded a standard of 10 grams = \frac{24}{90} = 0.27

\hat p_2 = sample proportion of cars driven at low altitudes who exceeded a standard of 10 grams = \frac{42}{380} = 0.11

n_1 = sample of cars driven at high altitudes = 90

n_2 = sample of cars driven at low altitudes = 380

So, the test statistics =  \frac{(0.27-0.11)-(0)}{\sqrt{\frac{0.27(1-0.27)}{90}+\frac{0.11(1-0.11)}{380} } }      

                                   =  3.234

The value of z-test statistics is 3.234.

7 0
3 years ago
The population of the United States was about 280 million in 2000 and about 310 million in 2010 . What was the annual rate of ch
storchak [24]
<span>In order to solve this you would need to take the difference in population and then divide by the difference of the number of years that have passed. So first we figure that there is a 30 million difference in population over the course of 10 years. So you would take 30 and divide by 10. Your problem would then appear as this 30/10=3 ... ( I removed all unnecessary zeros from the equation to simplify it). The answer is an annual rate of 3 million people per year (after adding back all necessary zeros to get back to the proper population number in the millions).</span>
7 0
3 years ago
What is the measure of BDC, given that figure ADCB is a rectangle?
Murrr4er [49]
We are asked to solve for the angle of BDC in the figure which is rectangle ACBD.

Since it is a rectangle, each corner has a 90°. Initially, it was given that angle BDA is equal to 50°. Then we can solve for BDC, such as the solution is shown below:

90° = ∠ BDC + ∠ BDA
90° = ∠BDC + 50°
∠BDC = 90° - 50°
∠ BDC = 40°

The answer is 40°.
7 0
3 years ago
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